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#1
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Simple replace command
I have a macro that deals with 9 different files one by one.
I have 2 columns in each file that should have its formulas' references adapted depending on the file I am treating. I used the replace comand, but it's not working. I tried several times and several ways... I just wanted to replace "$16;" by "$17;", "$18;",... etc which are filed in the variable substitution. If one has a tip... Thanks in advance, Daniel (Brazil) myUnion.Select myUnion.Replace What:="$16;", Replacement:=Substitution, LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False |
#2
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Simple replace command
Daniel,
Shouldn't it be $16: that is colon not semi-colon? -- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "dspilberg" wrote in message ... I have a macro that deals with 9 different files one by one. I have 2 columns in each file that should have its formulas' references adapted depending on the file I am treating. I used the replace comand, but it's not working. I tried several times and several ways... I just wanted to replace "$16;" by "$17;", "$18;",... etc which are filed in the variable substitution. If one has a tip... Thanks in advance, Daniel (Brazil) myUnion.Select myUnion.Replace What:="$16;", Replacement:=Substitution, LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False |
#3
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Simple replace command
I did not understand why. But it worked. Could you explain again? What is
colon? Thanks, Daniel "Bob Phillips" wrote: Daniel, Shouldn't it be $16: that is colon not semi-colon? -- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "dspilberg" wrote in message ... I have a macro that deals with 9 different files one by one. I have 2 columns in each file that should have its formulas' references adapted depending on the file I am treating. I used the replace comand, but it's not working. I tried several times and several ways... I just wanted to replace "$16;" by "$17;", "$18;",... etc which are filed in the variable substitution. If one has a tip... Thanks in advance, Daniel (Brazil) myUnion.Select myUnion.Replace What:="$16;", Replacement:=Substitution, LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False |
#4
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Simple replace command
I think it is because you are trying to change a cell reference, and these
are separated by colon, not semi-colon. -- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "dspilberg" wrote in message ... I did not understand why. But it worked. Could you explain again? What is colon? Thanks, Daniel "Bob Phillips" wrote: Daniel, Shouldn't it be $16: that is colon not semi-colon? -- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "dspilberg" wrote in message ... I have a macro that deals with 9 different files one by one. I have 2 columns in each file that should have its formulas' references adapted depending on the file I am treating. I used the replace comand, but it's not working. I tried several times and several ways... I just wanted to replace "$16;" by "$17;", "$18;",... etc which are filed in the variable substitution. If one has a tip... Thanks in advance, Daniel (Brazil) myUnion.Select myUnion.Replace What:="$16;", Replacement:=Substitution, LookAt:=xlPart, _ SearchOrder:=xlByRows, MatchCase:=False, SearchFormat:=False, _ ReplaceFormat:=False |
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