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Hi
This doesn't work (it runs, but gives a result of 0 instead of the correct answer) when the user responds with 54161 (for example): Sub HowMany() Dim res As String Dim myinput As String myinput = InputBox("Enter the CPT Code...") res = Evaluate("=CountIf(Ops, myinput)") MsgBox (res) End Sub This does work: Sub HowMany() Dim res As String Dim myinput As String 'myinput = InputBox("Enter the CPT Code...") res = Evaluate("=CountIf(Ops, 54161)") MsgBox (res) End Sub I've searched this group and googled, but can't find why or how to get the VBA for COUNTIF to accept a variable as a criteria.... Any idea how to get around this ? Thanks again C L Snyder |
#2
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Charles,
Try it this way: res = Evaluate("=CountIf(Ops, " & myinput & ")") I believe this way should also work: res = WorksheetFunction.CountIf(Range("Ops"), myinput) -- Hope that helps. Vergel Adriano "Charles L. Snyder" wrote: Hi This doesn't work (it runs, but gives a result of 0 instead of the correct answer) when the user responds with 54161 (for example): Sub HowMany() Dim res As String Dim myinput As String myinput = InputBox("Enter the CPT Code...") res = Evaluate("=CountIf(Ops, myinput)") MsgBox (res) End Sub This does work: Sub HowMany() Dim res As String Dim myinput As String 'myinput = InputBox("Enter the CPT Code...") res = Evaluate("=CountIf(Ops, 54161)") MsgBox (res) End Sub I've searched this group and googled, but can't find why or how to get the VBA for COUNTIF to accept a variable as a criteria.... Any idea how to get around this ? Thanks again C L Snyder |
#3
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I think I tried every permutation of "=", "&", etc but that one - it
works perfectly! Thanks CLS |
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