On Thu, 26 Apr 2007 16:30:03 -0700, Dave Runyan
wrote:

Thanks, Ron - as it is so often the problem was the nut holding the wheel. I
"learned" my regex using a freeware utility that had slightly different
syntax, so I had to convert many lines of expressions. Along the way I
somehow forgot that * is an enumerator, not a character placeholder - so I
was trying to capture (*) instead of (.*). As soon as I saw your fragment I
realized what the problem was.

Initially I ALSO had the parameters backwards in the method invocation
(having the search in a proprerty, and the input and replacement strings in
the call is just hard for me to grok it seems), but when I fixed that, I then
made the * error and the message I got was the same, 5018, with no helpful
text.

Okay - thanks again for your help - I will probably be asking something
again sooner than I imagine.

Well, I'm glad my efforts helped point you in a useful direction. There are
certainly some aspects of Regular Expressions as used in Perl, for example,
that are not replicated in VB.

Best wishes.
--ron