LinkBack Thread Tools Search this Thread Display Modes
Prev Previous Post   Next Post Next
  #1   Report Post  
Posted to microsoft.public.excel.programming
PO PO is offline
external usenet poster
 
Posts: 66
Default Using cmdlg xlDialogOpen

My code needs to know the path and filename to a workbook for later use. The
info is to be provided by the user.

I tried to use:

Application.Dialogs(xlDialogOpen).Show

but that only returns the value true or false.

I still want the dialog to show but instead of true or false I want the
dialog to return the path and filename to the workbook. Also I don't want
the file to open - I just need the path info.

Any ideas?

TIA
PO


 
Thread Tools Search this Thread
Search this Thread:

Advanced Search
Display Modes

Posting Rules

Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
xlDialogOpen get it to return Path DMc2005 Excel Discussion (Misc queries) 1 October 2nd 05 03:47 PM
xlDialogOpen get it to return Path DMc2005 Excel Programming 1 October 2nd 05 03:47 PM
xlDialogOpen.Show or Activeworkbook.Path? Mike Echo Excel Worksheet Functions 2 January 29th 05 09:51 AM
changing the title of an 'application.dialog(xldialogopen)' Reiner Giesen Excel Programming 0 November 20th 03 04:36 PM


All times are GMT +1. The time now is 10:43 PM.

Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
Copyright ©2004-2025 ExcelBanter.
The comments are property of their posters.
 

About Us

"It's about Microsoft Excel"