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#1
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Colored Cell
I need to create a macro that will display a color in a cell depending on the
condition of a different cell. For example if cell B1 has a 0 in it, A1 will turn red, otherwise it wont have a color. This needs to happen in about 4000 consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#2
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Colored Cell
Hi brownti
You can use CF See http://www.contextures.com/xlCondFormat01.html -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "brownti via OfficeKB.com" <u31540@uwe wrote in message news:6e7e1cf0ad1b7@uwe... I need to create a macro that will display a color in a cell depending on the condition of a different cell. For example if cell B1 has a 0 in it, A1 will turn red, otherwise it wont have a color. This needs to happen in about 4000 consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#3
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Colored Cell
I need to use six different colors...
Ron de Bruin wrote: Hi brownti You can use CF See http://www.contextures.com/xlCondFormat01.html I need to create a macro that will display a color in a cell depending on the condition of a different cell. For example if cell B1 has a 0 in it, A1 will turn red, otherwise it wont have a color. This needs to happen in about 4000 consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#4
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Colored Cell
You can use the change event in the sheet module then
Private Sub Worksheet_Change(ByVal Target As Range) Select Case Range("B1").Value Case 0: Range("A1:A4000").Interior.ColorIndex = 3 Case 1: Range("A1:A4000").Interior.ColorIndex = 5 Case 2: Range("A1:A4000").Interior.ColorIndex = 7 Case 3: Range("A1:A4000").Interior.ColorIndex = 9 Case 4: Range("A1:A4000").Interior.ColorIndex = 11 Case 5: Range("A1:A4000").Interior.ColorIndex = 13 Case Else: Range("A1:A4000").Interior.ColorIndex = xlColorIndexNone End Select End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "brownti via OfficeKB.com" <u31540@uwe wrote in message news:6e7e49cc53550@uwe... I need to use six different colors... Ron de Bruin wrote: Hi brownti You can use CF See http://www.contextures.com/xlCondFormat01.html I need to create a macro that will display a color in a cell depending on the condition of a different cell. For example if cell B1 has a 0 in it, A1 will turn red, otherwise it wont have a color. This needs to happen in about 4000 consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#5
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Colored Cell
Use this one, test first if B1 is the cell that is changed before you run the code
Private Sub Worksheet_Change(ByVal Target As Range) If Not Application.Intersect(Range("B1"), Target) Is Nothing Then Select Case Range("B1").Value Case 0: Range("A1:A4000").Interior.ColorIndex = 3 Case 1: Range("A1:A4000").Interior.ColorIndex = 5 Case 2: Range("A1:A4000").Interior.ColorIndex = 7 Case 3: Range("A1:A4000").Interior.ColorIndex = 9 Case 4: Range("A1:A4000").Interior.ColorIndex = 11 Case 5: Range("A1:A4000").Interior.ColorIndex = 13 Case Else: Range("A1:A4000").Interior.ColorIndex = xlColorIndexNone End Select End If End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "Ron de Bruin" wrote in message ... You can use the change event in the sheet module then Private Sub Worksheet_Change(ByVal Target As Range) Select Case Range("B1").Value Case 0: Range("A1:A4000").Interior.ColorIndex = 3 Case 1: Range("A1:A4000").Interior.ColorIndex = 5 Case 2: Range("A1:A4000").Interior.ColorIndex = 7 Case 3: Range("A1:A4000").Interior.ColorIndex = 9 Case 4: Range("A1:A4000").Interior.ColorIndex = 11 Case 5: Range("A1:A4000").Interior.ColorIndex = 13 Case Else: Range("A1:A4000").Interior.ColorIndex = xlColorIndexNone End Select End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "brownti via OfficeKB.com" <u31540@uwe wrote in message news:6e7e49cc53550@uwe... I need to use six different colors... Ron de Bruin wrote: Hi brownti You can use CF See http://www.contextures.com/xlCondFormat01.html I need to create a macro that will display a color in a cell depending on the condition of a different cell. For example if cell B1 has a 0 in it, A1 will turn red, otherwise it wont have a color. This needs to happen in about 4000 consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#6
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Colored Cell
I dont think I was totally clear. It more like if B1 = 0 then A1 is red, if
b2 = 0 then A1 is red etc...through 4000 rows. i think i need a loop that checks each row individually. i dont really understand how to create loops though. Ron de Bruin wrote: You can use the change event in the sheet module then Private Sub Worksheet_Change(ByVal Target As Range) Select Case Range("B1").Value Case 0: Range("A1:A4000").Interior.ColorIndex = 3 Case 1: Range("A1:A4000").Interior.ColorIndex = 5 Case 2: Range("A1:A4000").Interior.ColorIndex = 7 Case 3: Range("A1:A4000").Interior.ColorIndex = 9 Case 4: Range("A1:A4000").Interior.ColorIndex = 11 Case 5: Range("A1:A4000").Interior.ColorIndex = 13 Case Else: Range("A1:A4000").Interior.ColorIndex = xlColorIndexNone End Select End Sub I need to use six different colors... [quoted text clipped - 10 lines] consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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#7
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Colored Cell
Then we do it like this
I use the whole column here but you can change it to If Not Application.Intersect(Range("B1:B4000"), Target) Is Nothing Then Private Sub Worksheet_Change(ByVal Target As Range) If Not Application.Intersect(Range("B:B"), Target) Is Nothing Then Select Case Target.Value Case 0: Target.Offset(0, -1).Interior.ColorIndex = 3 Case 1: Target.Offset(0, -1).Interior.ColorIndex = 5 Case 2: Target.Offset(0, -1).Interior.ColorIndex = 7 Case 3: Target.Offset(0, -1).Interior.ColorIndex = 9 Case 4: Target.Offset(0, -1).Interior.ColorIndex = 11 Case 5: Target.Offset(0, -1).Interior.ColorIndex = 13 Case Else: Target.Offset(0, -1).Interior.ColorIndex = xlColorIndexNone End Select End If End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "brownti via OfficeKB.com" <u31540@uwe wrote in message news:6e7e8545e1aec@uwe... I dont think I was totally clear. It more like if B1 = 0 then A1 is red, if b2 = 0 then A1 is red etc...through 4000 rows. i think i need a loop that checks each row individually. i dont really understand how to create loops though. Ron de Bruin wrote: You can use the change event in the sheet module then Private Sub Worksheet_Change(ByVal Target As Range) Select Case Range("B1").Value Case 0: Range("A1:A4000").Interior.ColorIndex = 3 Case 1: Range("A1:A4000").Interior.ColorIndex = 5 Case 2: Range("A1:A4000").Interior.ColorIndex = 7 Case 3: Range("A1:A4000").Interior.ColorIndex = 9 Case 4: Range("A1:A4000").Interior.ColorIndex = 11 Case 5: Range("A1:A4000").Interior.ColorIndex = 13 Case Else: Range("A1:A4000").Interior.ColorIndex = xlColorIndexNone End Select End Sub I need to use six different colors... [quoted text clipped - 10 lines] consecutive cells. Probably be easiest if it just happens when the workbook is opened. Thanks in advance for any help. -- Message posted via http://www.officekb.com |
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