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...if Steve do not know how to do "brakes" meaning his
skill = 0 or null. Hi. Just some thoughts. In a Minimization problem, Solver would like to pick 0, as this minimizes the solution. One common option is to set it to a very high value, say 10000. When Solver takes a look at Steve & Brakes, the target cell is so high that this option is not considered. One technique I use is as follows. Many OR text books use the symbol "M" to represent a large penalty value. Therefore, I add a range-name constant "M" set to 10000. In the "Data" table, I use =M to represent an invalid option, together with a custom format to display "M" If one goes too high with the penalty, some problems work better with the Solver option "Use Automatic Scaling" turned on. -- HTH :) Dana DeLouis Windows XP & Office 2003 "romelsb" wrote in message ... Rick....that looks well....i got a theory that based on such sumproduct formula....it may not work if one of the mechanic has no skill on any one of the four category...try if steve do not know how to do "brakes" meaning his skill = 0 or null....it happens most of the time...then there may be another type of scenario.... -- "Bright minds are blessed to those who share them.."-rsb. "rick" wrote: I want to thank all for helping with this problem. I used the solver and the another 4 x4 array for variables to change to solve. Engine Trans Align Brakes Sam 45 34 23 45 Avery 48 30 36 37 Ben 30 48 40 41 Steve 38 34 30 31 Variables Engine Trans Align Brakes Total2 Available2 Sam 0 0 1 0 <==(sum)1 1 Avery 0 1 0 0 <==(sum)1 1 Ben 1 0 0 0 <==(sum)1 1 Steve 0 0 0 1 <==(sum)1 1 Total1 1 1 1 1 Available1 1 1 1 1 Constraints total1 =available1 total2 =available2 Lowest Time= 114 [=sumproduct(1st 4x4 array),(2nd 4x4 array)] romelsb wrote: you are right John.... SET TARGET : MIN orig data 4x4 : named as Data another 4x4 : named as CHG ----as the changing cells another cell : named SUM ----FORMULA IS "=SUM(CHG)" SAME OPTIONS CONSTRAINTS CHG=BIN SUM=4 ...thanks... -- "Bright minds are blessed to those who share them.."-rsb. "John Coleman" wrote: Dana DeLouis wrote: Hi Rick. Solver can do this, but you need helper cells. Your data is in a 4*4 grid. (Let's name it "Data") Make another 4*4 area nearby, and name it "Chg" (The Changing cells) Fill each cell in Chg with 1 for now. Add a Target cell with the formula =SUMPRODUCT(Data,Chg) (We note that Target should now show the total of all the cells in Data). For Solver, minimize the Target cell, by changing the Chg cells. Add the constraint that the Chg cells are Binary (Bin). Not needed here, and (since this looks like homework for an OR/MS course) possibly not desired. Assignment problems like this are a special case of a network flow problem, and it is known that if all constraints for such a problem are integral then the corresponding LP has integral solutions, so you don't need to model it as an ILP. But - you would still need to check assume nonnegative and assume linear in the options menu. This limits the cells to either 0 or 1. A "1" means that Solver picked that combination. However, we need to add Constraints to Chg cells. Each Row, and each Column in Chg can have only one "1". Select the Chg table, but expand it by 1 column to the right, and 1 row down. Hit the Autosum button, and delete the sum formula in the lower right corner. You now have Sum formulas for each Row, and each Column. For the vertical Sum formulas, add two constraints that this area is <1.01, and 0.99 For example, and the constraints like: F7:F10 < 1.01 F7:F10 0.99 The reason for not using just F7:F10 =1 is that Solver can't really work with exact integers, so we allow for a little slack. If the solver really can't handle equality constraints in a linear integer programming problem (which your formulation gives) then its implementation of the branch-and-bound algorithm is seriously defective. Doesn't the Solver have slack built in? I thought that was what the precision and tolerance boxes in the options menu were for. I don't think there is really any need to detract from the elegance of the model. This doesn't affect any results. Also, you do not need to do this for each individual cell. Solver applies the constraint to each cell in Range F7:F10. Now, add the same constraint for the horizontal sum Formulas. Under Solver's options, place a check on "Assume linear model." This allows Solver to work faster on these problems. I get the same results as Gary's Student. I like to add Conditional Formatting to my Data area. I like to use a formula that if the corresponding cell in Chg is 0.5, then add formatting (Bold, Color, etc). It's easier for me to see who does what, then looking at the table of 1's & 0's. Note that Excel's Solver is limited to only 200 changing cells. This limits an area to about 14*14 (=196). Solver is not very good using this technique when the problem is large. You can write macros that can loop to find slightly larger problems, but it's not easy. Let's look at 1 possible problem if we "assign the task to the most efficient worker for that task." These are hard to spot when the problem is large. Two people (A & B), and 2 tasks. A can do each task in {3,5} minutes. B can do each task in {7,1000} minutes. A is more efficient at the first task. B gets remaining task. Total time: 3+1000 = 1003 minutes. However, if we start by looking at the most inefficient, and give the first task to B, and the remaining task 2 to A, then total time is 7+5 = 12 minutes. This is what makes it difficult. Anyway, hope this helps. -- Dana DeLouis Windows XP & Office 2003 "rick" wrote in message oups.com... Hello, I am new to this group and hope you can help me. I have a problem that I am trying to solve. I am trying to use solver but not sure if I am setting up the model correctly. I have 4 workers Sam, Avery, Ben, and Steve and 4 different duties (Engine, Trans, Alignment, & Brakes) that the can be performed. Each person has a different average time(mins) to complete each task. I am trying to develop the formula to optimize who should do what to get the lowest amount of time. Engine Transmission Alignment Brakes Sam 45 34 23 45 Avery 48 30 36 37 Ben 30 48 40 41 Steve 38 34 30 31 Thoughts on the formula and contraints? |
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