hi all,

does anyone know how to convert from hexadecimal
00017fff
or
3

to binary
00000000000000010111111111111111
or
011

Many Thanks
sean

install the analysis toolpak add in, then enter this

=HEX2BIN("F",8)


--


Gary


"sean_f" wrote in message
ups.com...
hi all,

does anyone know how to convert from hexadecimal
00017fff
or
3

to binary
00000000000000010111111111111111
or
011

Many Thanks
sean

Unfortunately I cannot rely on users to have the tool pak installed.

Thanks

sean



Gary Keramidas wrote:
install the analysis toolpak add in, then enter this

=HEX2BIN("F",8)


--


Gary


"sean_f" wrote in message
ups.com...
hi all,

does anyone know how to convert from hexadecimal
00017fff
or
3

to binary
00000000000000010111111111111111
or
011

Many Thanks
sean

Hi sean_f;

Private Function HexToBin$(HexNum$)
Dim i As Byte, B As String * 1
Dim lNum&: lNum = Val("&H" & HexNum)
Do
If lNum And 2 ^ i Then B = "1" Else B = "0"
HexToBin = B & HexToBin
i = i + 1
Loop Until 2 ^ i lNum
End Function

Sub Test
MsgBox HexToBin("00017FFF"), 64
End Sub

Regards,
MP


"sean_f" a écrit dans le message de news:
...
hi all,

does anyone know how to convert from hexadecimal
00017fff
or
3

to binary
00000000000000010111111111111111
or
011

Many Thanks
sean

"sean_f" skrev i en meddelelse
ups.com...
hi all,

does anyone know how to convert from hexadecimal
00017fff
or
3

to binary
00000000000000010111111111111111
or
011

Many Thanks
sean


Hi Sean

Here's a general function to convert from one
number system to another:

Function Conv(Figure As String, _
FromBase As Integer, _
ToBase As Integer, _
Optional NumberOfDigits As Integer) As String
'Leo Heuser, October 1999
'=conv(Figure,FromBase,ToBase,NumberOfDigits)
'Examples: =conv(1234,6,16,6) or =conv("45ff",16,2,32)
'If NumberOfDigits is set to 0, left out or set to fewer digits
'than are in the result, the result will be displayed without
'leading zeroes.
'The setup will convert a number from base 2-16
'to another base 2-16, but the string Digits can be
'expanded to Z, and thereby covering base 2 through 36
'If the line "Figure = UCase(Figure)" is deleted, it's possible
'to place lower case letters in Digits to cover base 2-62.
'Please keep the above text, if you pass on this routine.

Dim Digits As String
Dim ToBaseTen As Long
Dim Dummy As Variant
Dim Counter As Integer
Dim Result As String
Conv = "Input error"
Digits = "0123456789ABCDEF"
If ToBase Len(Digits) Then Exit Function
Figure = UCase(Figure)
For Counter = 1 To Len(Figure)
Dummy = Mid$(Figure, Counter, 1)
If InStr(Left$(Digits, FromBase), Dummy) = 0 Then
Exit Function
Else
ToBaseTen = ToBaseTen + (InStr(Digits, Dummy) - 1) * _
(FromBase ^ (Len(Figure) - Counter))
End If
Next Counter
While ToBaseTen 0
Result = Mid$(Digits, (ToBaseTen Mod ToBase) + 1, 1) & Result
ToBaseTen = Int(ToBaseTen / ToBase)
Wend
If NumberOfDigits = 0 Or NumberOfDigits < Len(Result) Then
Conv = Result
Else
Conv = Right$(String$(NumberOfDigits - Len(Result), "0") & _
Result, NumberOfDigits)
End If
End Function


--
Best regards
Leo Heuser

Followup to newsgroup only please.