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Thx for your help Tom,
I managed to find another way in another group: Sub MostRecentFile() With Application.FileSearch ..NewSearch ..LookIn = "\\jcfilc01\group\energy\Pricing Models\Curve Generation\" ..Filename = "*.xls" If .Execute(SortBy:=msoSortByLastModified, _ SortOrder:=msoSortOrderDescending) 0 Then Workbooks.Open .FoundFiles(1) Else MsgBox "No can do!" End If End With End Sub Cheers, BB Tom Ogilvy wrote: this pseudo code should give you a start. dim dt as Date, sPath as String Dim sName as String Dim s1 as String, s2 as String Dim bk1 as Workbook, bk2 as Workbook sPath = "C:\myfolder\" sName = dir(sPath & "*.xls") do while sname < "" ' parse out the date or use filedatetime dt = filedatetime(sPath & sName) if dt maxDate then if maxDate max2ndDate then max2ndDate = maxDate s2 = s1 end if maxDate = dt s1= sName elseif dt Max2ndDate then Max2ndDate = dt s2 = sName end if sName = dir Loop if s1 < "" then set bk1 = Workbooks.open(spath & s1) end if if s2 < "" then set bk2 = workbooks.open(spath & s2) end if -- Regards, Tom Ogilvy " wrote: Just in case (I forgot to precise), what I need is a VBA code to include in a procedure BigBen wrote: Hi all, do any one of you know how to open the latest recorded .xls file in a given folder? In fact, in my case my files all have a date in their name (corresponding to the date they have been created), unfortunately this is not always done on a daily basis. But I always need to open the two latest files. thx for your help, cheers, BigBen |
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