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#1
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Multiple Combo Box Indices?
I am working with a combo box populated with a collection from a
spreadsheet which has some blank cells (intentional). I would like for the combo box to not display the blank rows (which I've managed to get it to do), and also for another index to count the total number of rows. I can't use the index for the combo box, as it omits the blank rows. Is it possible to have two indexes (one for display and one for true row counting)? I need to keep the position in the collection with the row counting. Many thanks, Louis |
#2
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Multiple Combo Box Indices?
Assuming a combobox from the control toolbox toolbar.
there is no built in support for it. You could put in two columns in the list and maintain the true row there. You can hide that column using the ColumnWidths setting. -- Regards, Tom Ogilvy "ll" wrote: I am working with a combo box populated with a collection from a spreadsheet which has some blank cells (intentional). I would like for the combo box to not display the blank rows (which I've managed to get it to do), and also for another index to count the total number of rows. I can't use the index for the combo box, as it omits the blank rows. Is it possible to have two indexes (one for display and one for true row counting)? I need to keep the position in the collection with the row counting. Many thanks, Louis |
#3
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Multiple Combo Box Indices?
Thanks Tom,
If the two columns were in the same listing, would the selection of the visible column items generate the index, or could it be set so that the visible items could reference the hidden column, which would generate the index? Thanks again, Louis |
#4
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Multiple Combo Box Indices?
you just read the value (row number) from the list and use it. There is no
generating. -- Regards, Tom Ogilvy "ll" wrote in message ups.com... Thanks Tom, If the two columns were in the same listing, would the selection of the visible column items generate the index, or could it be set so that the visible items could reference the hidden column, which would generate the index? Thanks again, Louis |
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