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#1
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I have this formula typed in for a cell. It gives me the result I
need, but when there's no input the #Value! shows up. How would I change up the formula so the errors don't show? =IF(B22<0,B22,IF(B23-B22,"$0.00",B23-B22)) cheers, day |
#2
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Hi, check to see if the values in B23 & B22 are text. I would also take
a look at your embeded if statement: 'IF(B23-B22'. HTH--Lonnie M. |
#3
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I think you'll only get that error if either of the cells is not blank or
numeric. If either cell has a space or an alphabetic character, you'll get the error. So check the contents first Maybe: =IF(AND(ISNUMBER(B22),ISNUMBER(B23)),IF(B22<0,B22, IF(B23-B22,"$0.00",B23-B22)),"Problem") Regards Trevor "day" wrote in message ups.com... I have this formula typed in for a cell. It gives me the result I need, but when there's no input the #Value! shows up. How would I change up the formula so the errors don't show? =IF(B22<0,B22,IF(B23-B22,"$0.00",B23-B22)) cheers, day |
#4
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I checked the cells and they are both set for currency. So, I tried
Trevor's formula and it worked great. Thanks guys... I never knew that Excel can be so intriguing. I love it. day |
#5
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Whoops... now it won't subtract at all, it just shows"problem" It
seems like it's not reading the second nested problem. How can I change it so it does? cheers day |
#6
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So never mind.. I think I solved it for the mean time. I used the
following only b/c I don't know how to use the other ISNUM, AND OR.... =IF(B6=-(B9),B6,IF(B6<0, (B9+B6),IF(B6=0,"$0.00",(B9*B7)-B6))) this is fun |
#7
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![]() It's because your nested IF doesn't make sense. You have IF(B23-B22,"$0.00",B23-B22) It's the first B23-B22 that's causing the problem Did you intend something like: IF(B23<B22,"$0.00",B23-B22) ? or IF(B23-B22<0,"$0.00",B23-B22) ? -- Cutter ------------------------------------------------------------------------ Cutter's Profile: http://www.excelforum.com/member.php...fo&userid=9848 View this thread: http://www.excelforum.com/showthread...hreadid=512851 |
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