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Hi Hypatia,
when I replaced that with "Wkt" just to see if it would work, it didn't.< It does depend on the "Wkt#" and the reason it didn't work was you probably kept the Number of Characters argument of the "Left" function equal to 1, so, you have to change that line of code to : If Left(SheetArray(iRowCounter, iColumnCounter), 3) = "Wkt" Then for it to work. Notice the 3 ('Wkt" has 3 characters) where previously there was a 1. Correct if I'm wrong, if my memory serves me correct, you are not wanting either the Wkt# or the series of underscores in the following cell to appear in a new version for use at your workplace. One way of achieving this is to include a line of code in that version which makes the font color in those cells the same as the cell interior color (icolor). This way they're still there, just not visible on screen or printed page (I assume). The new code follows: Public Sub ColorYear() Dim iRowCounter As Long, iColumnCounter As Long Dim SheetArray As Variant SheetArray = Range("A1:H1430") For iRowCounter = 3 To UBound(SheetArray) For iColumnCounter = 1 To UBound(SheetArray, 2) If Left(SheetArray(iRowCounter, iColumnCounter), 1) = "W" Then iYearIndex = Year(Cells(iRowCounter - 1, iColumnCounter + 1).Value) Mod 4 If iYearIndex = 0 Then Let icolor = 19 '2008,2012,2016 If iYearIndex = 1 Then Let icolor = 40 '2005,2009,2013 If iYearIndex = 2 Then Let icolor = 20 '2006,2010,2014 If iYearIndex = 3 Then Let icolor = 35 '2007,2011,2015 Range(Cells(iRowCounter - 2, iColumnCounter), Cells(iRowCounter, iColumnCounter + 1)) _ .Interior.ColorIndex = icolor Range(Cells(iRowCounter, iColumnCounter), Cells(iRowCounter, iColumnCounter + 1)) _ .Font.ColorIndex = icolor End If Next iColumnCounter Next iRowCounter End Sub If you run this code but then you change your mind because you want them visible again you can change ".Font.ColorIndex = icolor" in the last line of the loop to ".Font.ColorIndex = 0" then run the code again. Let me know how this goes. Ken Johnson |
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