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![]() =INDIRECT(ADDRESS(MATCH(A:A,Sheet2!A:A,0)+1,4,4,1, "Sheet2")) I need help changing this a little, once it finds a match it looks down 2 rows and over 7 rows for the cell containg the word "Productive" and then go 1 cell over to the right and that is the value I need. thanks for the help -- Teerings3 ------------------------------------------------------------------------ Teerings3's Profile: http://www.excelforum.com/member.php...o&userid=29560 View this thread: http://www.excelforum.com/showthread...hreadid=492726 |
#2
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I think that your Match function is incorrect, the match function requires
the lookup value as the first argument, not a range of cells. Try match("Productive", Sheet2!A:A,false) and then mess around with the offsets to get the correct address. HTH Martin "Teerings3" wrote: =INDIRECT(ADDRESS(MATCH(A:A,Sheet2!A:A,0)+1,4,4,1, "Sheet2")) I need help changing this a little, once it finds a match it looks down 2 rows and over 7 rows for the cell containg the word "Productive" and then go 1 cell over to the right and that is the value I need. thanks for the help -- Teerings3 ------------------------------------------------------------------------ Teerings3's Profile: http://www.excelforum.com/member.php...o&userid=29560 View this thread: http://www.excelforum.com/showthread...hreadid=492726 |
#3
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![]() Thanks, But the first match is employee # and then it needs to look in a range of cells based on that location to find the word "productive" get that address and the value I need is one cell over. -- Teerings3 ------------------------------------------------------------------------ Teerings3's Profile: http://www.excelforum.com/member.php...o&userid=29560 View this thread: http://www.excelforum.com/showthread...hreadid=492726 |
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