What I'd like to do is, if the last letter of what is inputed into a
cell is the "+" symbol. Then delete it.


I have a cell defined by:
Sheet12.Cells(11, 2) = d & "+" + l & "+" + w & "+" + s


Here's what i get fromt that cell.
..5D + 2L + 3W + 2S


if i change it and s = 0 i get
..5D + 2L + 3W +


i want to get
..5D + 2L + 3W


So i was hoping maybe there was a command, to delete a space off the
end of a cell using and IF statement.


IF last letter is a "+" , delete 1-2 spaces of the end of the cell.

Suppose to be titled

"Deleting last letter OF a cell"

dim myStr as string

mystr = ".5D + 2L + 3W + "
'extra spaces, too

mystr = trim(mystr) 'gets rid of leading and trailing spaces

if right(mystr,1)="+" then
mystr = trim(left(mystr,len(mystr)-1))
'also cleans up trailing spaces with the trim.
end if

msgbox "***" & mystr & "***"



Kevin O'Neill wrote:

What I'd like to do is, if the last letter of what is inputed into a
cell is the "+" symbol. Then delete it.

I have a cell defined by:
Sheet12.Cells(11, 2) = d & "+" + l & "+" + w & "+" + s

Here's what i get fromt that cell.
.5D + 2L + 3W + 2S

if i change it and s = 0 i get
.5D + 2L + 3W +

i want to get
.5D + 2L + 3W

So i was hoping maybe there was a command, to delete a space off the
end of a cell using and IF statement.

IF last letter is a "+" , delete 1-2 spaces of the end of the cell.

--

Dave Peterson

right click on the sheet tab and select view code

in the left dropdown at the top of the resulting module, select
WorkSheet
and in the right dropdown select
Change (not SelectionChange)

then put code in this sub (the change event) like this

Dim s as String
If Target.count 1 then exit sub
if isempty(target) then exit sub
if Target.Column = 2 then
s = Trim(Target.Value)
if Right(s,1) = "+" then
Application.enablevents = False
Target.Formula = Trim(Left(s,len(s)-1))
Application.EnableEvents = True
end if
end if


as written works only in column B. Change to suit

--
Regards,
Tom Ogilvy






"Kevin O'Neill" wrote in message
ups.com...
Suppose to be titled

"Deleting last letter OF a cell"

Ah Aswome guys got that working good. There's that other tricky part,
which I think will actually be tricky.

If my result is:
..5D + .5L + 2S

convert that to:
..5(D+L) +2S

What do you think?