True, but why lumber along with that. (which doesn't work in xl97 and
earlier by the way)

Select the column and do

Edit=Replace
What ***<spc
With REM<spc

and don't select entire word.

But then he asked about using MID.

--
Regards,
Tom Ogilvy



"NickHK" wrote in message
...
Tom,
Any need to check really ?

c.Value = Replace(c.Value, "*** ", "REM ")

Nick

"Tom Ogilvy" wrote in message
...
Sub CommentOutWithRem()

Dim c as Range
Dim sStr as String
For each c in Range("a1:a2150")
If Mid(c,1,1)="*" Then
sStr = c.Value
Mid(sStr,1,3) = "REM"
c.value =sStr
End if
next

--
Regards,
Tom Ogilvy


"davidm" wrote in
message ...

I have tried to deploy the 2 MID concepts-Statement vs. Function to
effect replacements in a range-----and have gotten stuck in a spin.

Consider, lines of string like:

*** CODE1 Begins here ****
<some other lines
*** CODE2 Begins here ****
<some other lines
etc. etc. etc.

occupying Range("A1:A2150").

I need to convert to comments all lines beginning with asterick (*)
and
have them read as follows:

Rem CODE1 Begins here ****
<some other lines
Rem CODE2 Begins here ****

The code I stitched up (largely to test out the nuances of the MID
FUNCTION and MID STATEMENT) is:


Sub CommentOutWithRem()

Dim c as variant ' as Range or Object produces MisMatch errors
For each c in Range("a1:a2150")
If Mid(c,1,1)="*" Then Mid(c,1,3)="REM"
*'the sticky point follows in making an assignment:
'note, no action takes place if the code ends here.
*
c.value =c.value 'error: object required
c.Value = Mid(c, 1, 3) = "REM" 'error: object required
End if

next

End sub


Can someone kindly unknot the problem here? [I have very easily
applied
other routine constructs to do what I want the code to do but there
are
obviously useful lessons to be learnt about theinteraction of the MID
function and its kin, the statement.

Many thanks in advance.


--
davidm

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