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yes, i pasted old code and didn't notice. i thought i copied the code after
i changed it but i guess i didn't. this is what i came up with and didn't end up posting LastRow = Cells(Rows.Count, "A").End(xlUp).Row For i = 1 To LastRow Range("a" & LastRow).Select ActiveCell.Formula = RTrim(ActiveCell.Formula) LastRow = LastRow - 1 Next i -- Gary "Norman Jones" wrote in message ... Hi Gary, Your procedure only acts on the A1 cell as your code uses the instruction: ActiveCell.Formula = RTrim(ActiveCell.Formula) and, having pre-selected A1, you do not change the active cell. --- Regards, Norman "Gary Keramidas" wrote in message ... something like this may work if your data is in column A Option Explicit Dim rText As String Dim LastRow As Long Dim i As Long Sub Macro1() LastRow = Cells(Rows.Count, "A").End(xlUp).Row Range("a1").Select For i = 1 To LastRow ActiveCell.Formula = RTrim(ActiveCell.Formula) Next i End Sub -- Gary "Emory Richter" wrote in message om... I would like to use RTrim to remove spaces from a list of single words. Every example of RTrim I can find on the web seems to be for a paticular fixed string like "Hello World ". If I want to use: RTrim( text ) with 'text' as a variable to loop down a list, if possible and remove the trailing spaces can I substitute something for 'text' to identify the cell contents ? That is, how would the following look? Sub Macro1() Do Until ActiveCell.Formula = "" ActiveCell.Offset(1, 0).Select RTrim( text ) Loop Thank you, Emory |
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