That's not it Jim, letters for the column argument are perfectly acceptable,
so that is not the cause (at least in English language versions), although,
I'll bet that if your suggestion will work.

I think that it is something to do with that the language version, but
without a Spanish or opther language version, it is difficult to try.

Baldermo,

Record a simple macro that selects a cell What does the code say? Does it
say Range("A1"Q).Select say, or something else.

--

HTH

RP
(remove nothere from the email address if mailing direct)


"Jim Thomlinson" wrote in message
...
The second argument of your cells uses letters when it expects a number
(similar to the code you have at the bottom of your post

For I = 0 to 10
Cells(1 + I, 1).Value = I +1 'remove A
Cells(1 + I, 2).Value = Array_Bool(I) 'remove B
Cells(1 + I, 3).Value = Array_Int(I) 'remove C
Next I

--
HTH...

Jim Thomlinson


"baldomero" wrote:


Hello, I am trying to write the values of two arrays (one boolean and
the other integer of one dimension of 50 values each one) to a
worksheet.

the code i use is this:

For I = 0 to 10
Cells(1 + I, "A").Value = I +1
Cells(1 + I, "B").Value = Array_Bool(I)
Cells(1 + I, "C").Value = Array_Int(I)
Next I

The problem I get is that Excel gives me an error:

' Error '9' occurred in execution time. '
' Subindex out of interval '

(translated from spanish)

the third line is marked in yellow with the debug option, and if I mark
it as comment, then the same happens with the fourth line.

variables are declared this way:

Dim Array_Bool(50) As Boolean
Dim Array_Int(50) As Integer
Dim I As Integer

Also, it works if I manually write this:
Cells(25, 2).Value = Array_Bool(0)
Cells(26, 2).Value = Array_Bool(1)
Cells(27, 2).Value = Array_Bool(2)
Cells(28, 2).Value = Array_Bool(3)
Cells(29, 2).Value = Array_Bool(4)
Cells(30, 2).Value = Array_Bool(5)
Cells(31, 2).Value = Array_Bool(6)
Cells(32, 2).Value = Array_Bool(7)
Cells(33, 2).Value = Array_Bool(0)

Cells(25, 3).Value = Array_Int(0)
Cells(26, 3).Value = Array_Int(1)
Cells(27, 3).Value = Array_Int(2)
Cells(28, 3).Value = Array_Int(3)
Cells(29, 3).Value = Array_Int(4)
Cells(30, 3).Value = Array_Int(5)
Cells(31, 3).Value = Array_Int(6)
Cells(32, 3).Value = Array_Int(7)
Cells(33, 3).Value = Array_Int(0)



Shouldn't the first code and the second one produce the same result??


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baldomero
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