Home |
Search |
Today's Posts |
#2
![]()
Posted to microsoft.public.excel.programming
|
|||
|
|||
![]()
Dim AnyString, MyStr
AnyString = "08/16/2005 18:38:32.300" ' Define string. MyStr = Left(AnyString, 11) HTH Andi "Jonathan Dunne" wrote in message ... Hi all I have a bunch of cells which contain both date and time e.g. 08/16/2005 18:38:32.300 08/16/2005 18:38:32.315 08/16/2005 18:38:34.308 I am wondering what is the correct procedure to remove the first 11 characters from each cell? I can't do a simple find and replace as the date will change. Thanks in advance Jonathan |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
How do I remove the last 4 characters within a cell | Excel Discussion (Misc queries) | |||
How do I remove new line characters from a cell? | Excel Discussion (Misc queries) | |||
Remove Characters from a cell | Excel Worksheet Functions | |||
remove non-numeric characters from a cell | Excel Discussion (Misc queries) | |||
remove last three characters of cell | Excel Discussion (Misc queries) |