Need some handy vba code to loop through the columns of a worksheet and
identify which column letter I am currently in, rather than the column
number. Any ideas.

Thanks,

Hi,
Here are 2 function that do that in a different way. One take the column
number a parameter, the other one takes the cell as parameter.

'--------------------------------------------------------------
Function ColChar(i As Long) As String
ColChar = IIf(i 26, Chr((i - 1) \ 26 + 64), "") & _
Chr((i - 1) Mod 26 + 65)
End Function

Function colChar2(cell As Range) As String
colChar2 = cell.Parent.Cells(1, cell.Cells(1).Column).Address(False, False)
colChar2 = Left(colChar2, Len(colChar2) - 1)
End Function
'------------------------------------------------------------------
--
Regards,
Sébastien
<http://www.ondemandanalysis.com


"Steve" wrote:

Need some handy vba code to loop through the columns of a worksheet and
identify which column letter I am currently in, rather than the column
number. Any ideas.

Thanks,

This will convert the column number to the letter(s):

Function Number2Letter(ByVal n As Long) As String

'returns the Excel sheet column letter given a number
'----------------------------------------------------

If n 0 And n < 257 Then
Number2Letter = Split(Cells(n).Address, "$")(1)
Else
Number2Letter = Error(9) ' Subscript out of range
End If

End Function

I take you know how to get the column number of the active cell.

RBS



"Steve" wrote in message
...
Need some handy vba code to loop through the columns of a worksheet and
identify which column letter I am currently in, rather than the column
number. Any ideas.

Thanks,