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And if you will store a row number in the variable, better to use a type
Long, or it might overflow. -- HTH RP (remove nothere from the email address if mailing direct) "NickHK" wrote in message ... Neal, Small point, but fromrow is declared as a Variant, whilst torow is an Integer, which is not what you mean, I think. You need to explicitly state the type of each variable, otherwise it defaults to a Variant. i.e. Dim fromrow as Integer Dim torow As Integer NickHK "Neal Zimm" wrote in message ... I tried to define an object representing a variable number of rows that are to be cut and inserted into another sheet. I got a type mismatch error on the code below. In the module where this code is going to go, the variables fromrow and to row are available and 'working'. I am a novice at 'object definition'. Help will be appreciated. Dim insertrange As range Dim fromrow, torow As Integer fromrow = 21: torow = 40 Set insertrange = Rows("&fromrow:&torow") ' Rows("21:40").Select trying to 'replace' this line of code insertrange.Select 'with this line of code Selection.Cut Sheets("new").Select range("A41").Select Selection.Insert Shift:=xlDown -- Neal Z |
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