I posted a message before asking how to find the column within a range which
held a six digit number. Tom Ogilvy kindly provided some codes as below
Dim ans as String, num as Long
Dim res as Variant
ans = Inputbox("Enter 6 digit number")
if isnumeric(ans) and len(trim(ans)) = 6 then
num = clng(ans)
res = application.Match(num, range("A1:E1"),0)
if not iserror(res) then
col = range("A1")(1, res).Column
else
msgbox "Not found"
end if
End if

This gives me the column number. But I would like the corresponding letter
of the column. For example If the sis dogit number was in column G, I would
like to update 3 cells in column G (e.g. range("G5").select ActiveCell =
"Done" Range("G7").Select ActiveCell = "OK" and so on) If column was H then
I would update H5, H7 and so on. How can I do this in VB?

Thank you
Prema