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#1
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Need to write a program to open a filename...
I want to write a VBA program that will automatically reference a date in a
certain cell and then use the data in the cell to be able to locate a file and open it. Example: Cell (1,2) has the data of: 12/31/04 Based on this info, the filename I wish to open is called 12-04.xls and is located in the following location: S:Accounting\Monthly Report\ How do I get VBA to automatically open the 12-04.xls file based on the data in that cell? Remember that a future time the data in that cell will change to a different date such as 02/28/05. In which case I would wish the program to open 02-05.xls located in the same folder location. |
#2
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Need to write a program to open a filename...
workbooks.open filename:= "S:\Accounting\Monthly Report\" & Range("A1").Text
& ".xls" -- HTH RP (remove nothere from the email address if mailing direct) "Flop" wrote in message ... I want to write a VBA program that will automatically reference a date in a certain cell and then use the data in the cell to be able to locate a file and open it. Example: Cell (1,2) has the data of: 12/31/04 Based on this info, the filename I wish to open is called 12-04.xls and is located in the following location: S:Accounting\Monthly Report\ How do I get VBA to automatically open the 12-04.xls file based on the data in that cell? Remember that a future time the data in that cell will change to a different date such as 02/28/05. In which case I would wish the program to open 02-05.xls located in the same folder location. |
#3
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Need to write a program to open a filename...
Hi Bob:
Thanks for the response. The VBA compiler seems to be having a problem wit the last part of the code at: & ."xls" Any idea why? Thanks! "Flop" wrote: I want to write a VBA program that will automatically reference a date in a certain cell and then use the data in the cell to be able to locate a file and open it. Example: Cell (1,2) has the data of: 12/31/04 Based on this info, the filename I wish to open is called 12-04.xls and is located in the following location: S:Accounting\Monthly Report\ How do I get VBA to automatically open the 12-04.xls file based on the data in that cell? Remember that a future time the data in that cell will change to a different date such as 02/28/05. In which case I would wish the program to open 02-05.xls located in the same folder location. |
#4
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Need to write a program to open a filename...
Nevermind, figured it out. Thanks for your help.
"Flop" wrote: I want to write a VBA program that will automatically reference a date in a certain cell and then use the data in the cell to be able to locate a file and open it. Example: Cell (1,2) has the data of: 12/31/04 Based on this info, the filename I wish to open is called 12-04.xls and is located in the following location: S:Accounting\Monthly Report\ How do I get VBA to automatically open the 12-04.xls file based on the data in that cell? Remember that a future time the data in that cell will change to a different date such as 02/28/05. In which case I would wish the program to open 02-05.xls located in the same folder location. |
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