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Default programming of matrix formulas in vba

Incorrect documentation is sometimes a PITA, huh?

keepITcool wrote:

Dave,

you are correct,
but worse... my r1c1 conversion is lacking
the relativeto argument, making it work only
when a1 is activecell.

Sub DoArrayFmlR1C1()
Dim sFml$
sFml = "=IF(A2:A6<B1:D1,1,0)"
Range("g1:g10").FormulaArray = _
Application.ConvertFormula(sFml, xlA1, xlR1C1, , Range("g1"))
End Sub

so I'll use a1 notation..

--
keepITcool
| www.XLsupport.com | keepITcool chello nl | amsterdam

Dave Peterson wrote :

VBA's help isn't quite true with the R1C1 reference style for
arrayformulas.

This version of KeepItCool's routine worked fine for me:

Option Explicit
Sub DoArrayFm2A()
Dim sFml$
sFml = "=IF(A2:A6<B1:D1,1,0)"
Range("b2:d6").FormulaArray = sFml
End Sub




thokel wrote:

hi

I use the formula {=if(A2:A6<B1:D1);1;0} to fill the cells b2:d6
with the information whether the values in column A are smaller
than the values given in row 1.

Now I want to program this formula in VBA (without running through
"while - wend" or "for- next" loops. This would be advantegous if
one have to handle with big data files.

But - I don't how to do this.
Of course I've started with introducing the arrays. But then ..?

Thanks - Thomas


--

Dave Peterson


 
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