mkdir problem
 

did you declare a variable as Right or create a sub named Right.

--
Regards,
Tom Ogilvy

"Keivn Green" wrote in message
...
When I try to use this command in a macro to create a directory that is
the
last for digits of the activecell it says " Wrong number of arguments or
invalid property assignment."
Here is the line in the code..
MkDir ("C:\test\" & RIGHT(ActiveCell.Text, 4))

If the active cell says 12345678 teh it should make a directory called
c:\test\5678

Any ideas why this doesnt work?

mkdir problem
 

It still sounds like you have RIGHT declared as a variable or as a function
someplace or are using it as a variable (perhaps unintentionally).

I would suspect you don't have Option Explicit declared at the top of each
module.

--
Regards,
Tom Ogilvy

"Keivn Green" wrote in message
...
I had the command in a private sub in a user form. when I put the command
in
a sub in a module and called that sub then it worked. HMM

"Keivn Green" wrote:

Strange. it works fine if I change it to LEFT but it wont do RIGHT.

What kind of declarations do I need to make if RIGHT is supposed to be a
built in procedure?

"Tom Ogilvy" wrote:

did you declare a variable as Right or create a sub named Right.

--
Regards,
Tom Ogilvy

"Keivn Green" wrote in message
...
When I try to use this command in a macro to create a directory that
is
the
last for digits of the activecell it says " Wrong number of
arguments or
invalid property assignment."
Here is the line in the code..
MkDir ("C:\test\" & RIGHT(ActiveCell.Text, 4))

If the active cell says 12345678 teh it should make a directory
called
c:\test\5678

Any ideas why this doesnt work?

mkdir problem
 

Does the function work as "VBA.RIGHT(ActiveCell.Text, 4)" ?

Keivn Green wrote:

I had the command in a private sub in a user form. when I put the command in
a sub in a module and called that sub then it worked. HMM

"Keivn Green" wrote:


Strange. it works fine if I change it to LEFT but it wont do RIGHT.

What kind of declarations do I need to make if RIGHT is supposed to be a
built in procedure?

"Tom Ogilvy" wrote:


did you declare a variable as Right or create a sub named Right.

--
Regards,
Tom Ogilvy

"Keivn Green" wrote in message
...

When I try to use this command in a macro to create a directory that is

the

last for digits of the activecell it says " Wrong number of arguments or
invalid property assignment."
Here is the line in the code..
MkDir ("C:\test\" & RIGHT(ActiveCell.Text, 4))

If the active cell says 12345678 teh it should make a directory called
c:\test\5678

Any ideas why this doesnt work?