I have a funcion call replacewords() that removes words form sentneces
if they appear in another cell. I want to highlight those cells where
the macro fails to find a word. To this end, I add the following code
to the function...

' Highlight those ENTRIES where a word was not located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With

but it doesn't seem to be doing anything to the cell formats at all.
The macro itself works, but I can't get it to have any effect on cell
formats.

Any ideas? Cheers,

Chris

Here is the entire function...

Option Explicit

Function replacewords(rng As Range, rng2 As Range, _
Optional WithString As String = "...") As
String

Dim mySent As String
Dim myEnt As String
Dim newSent As String
Dim sentArray As Variant
Dim entArray As Variant
Dim i As Integer
Dim j As Integer
Dim entnum As Integer
Dim mySpace As String

myEnt = rng(1).Value
mySent = rng2(1).Value
newSent = ""

sentArray = Split(mySent, " ", , vbTextCompare)
entArray = Split(myEnt, " ", , vbTextCompare)

i = 0
j = 0

entnum = UBound(entArray, 1) - LBound(entArray, 1) + 1

'if only one word in ENTRY field and it appears in the sentence then
'replace the word with "..." if identical
If entnum = 1 And InStr(1, mySent, myEnt, vbTextCompare) Then
newSent = Replace(mySent, myEnt, "...", 1, 1, vbTextCompare)
GoTo endgame
End If

'if more than one word in ENTRY and exact entry appears in sentence
then
'replace each word with amount of "..." as was words in entry
If InStr(1, mySent, myEnt, vbTextCompare) Then
For i = 1 To entnum
mySpace = mySpace & "... "
Next i
newSent = Replace(mySent, myEnt, mySpace, 1, 1, vbTextCompare)
GoTo endgame
End If

'Otherwise, loop through words in sentence and built a new setence
'where matching or near matching words with a replaced by "... "
For j = 0 To UBound(sentArray)
For i = 0 To UBound(entArray)
If LCase(entArray(i)) = LCase(sentArray(j)) Then
newSent = newSent & "... "
GoTo exitloop
End If
If LCase(Mid(entArray(i), 1, 3)) = LCase(Mid(sentArray(j), 1,
3)) Then
newSent = newSent & "... "
GoTo exitloop
End If
' Highlight those ENTRIES where a word was not located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With
Next i
newSent = newSent & sentArray(j) & " "
exitloop:
Next j

endgame:

newSent = Replace(newSent, " ", " ")

replacewords = newSent

End Function

untested but try replacing rng with i
I think that vb cant associate rng with i and therfore
does nothing. I'm guessing. and i don't have your data to
test it.
-----Original Message-----
I have a funcion call replacewords() that removes words
form sentneces
if they appear in another cell. I want to highlight those
cells where
the macro fails to find a word. To this end, I add the
following code
to the function...

' Highlight those ENTRIES where a word was not
located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With

but it doesn't seem to be doing anything to the cell
formats at all.
The macro itself works, but I can't get it to have any
effect on cell
formats.

Any ideas? Cheers,

Chris

Here is the entire function...

Option Explicit

Function replacewords(rng As Range, rng2 As Range, _
Optional WithString As String
= "...") As
String

Dim mySent As String
Dim myEnt As String
Dim newSent As String
Dim sentArray As Variant
Dim entArray As Variant
Dim i As Integer
Dim j As Integer
Dim entnum As Integer
Dim mySpace As String

myEnt = rng(1).Value
mySent = rng2(1).Value
newSent = ""

sentArray = Split(mySent, " ", , vbTextCompare)
entArray = Split(myEnt, " ", , vbTextCompare)

i = 0
j = 0

entnum = UBound(entArray, 1) - LBound(entArray, 1) + 1

'if only one word in ENTRY field and it appears in the
sentence then
'replace the word with "..." if identical
If entnum = 1 And InStr(1, mySent, myEnt, vbTextCompare)
Then
newSent = Replace(mySent, myEnt, "...", 1, 1,
vbTextCompare)
GoTo endgame
End If

'if more than one word in ENTRY and exact entry appears
in sentence
then
'replace each word with amount of "..." as was words in
entry
If InStr(1, mySent, myEnt, vbTextCompare) Then
For i = 1 To entnum
mySpace = mySpace & "... "
Next i
newSent = Replace(mySent, myEnt, mySpace, 1, 1,
vbTextCompare)
GoTo endgame
End If

'Otherwise, loop through words in sentence and built a
new setence
'where matching or near matching words with a replaced
by "... "
For j = 0 To UBound(sentArray)
For i = 0 To UBound(entArray)
If LCase(entArray(i)) = LCase(sentArray(j)) Then
newSent = newSent & "... "
GoTo exitloop
End If
If LCase(Mid(entArray(i), 1, 3)) = LCase(Mid
(sentArray(j), 1,
3)) Then
newSent = newSent & "... "
GoTo exitloop
End If
' Highlight those ENTRIES where a word was not
located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With
Next i
newSent = newSent & sentArray(j) & " "
exitloop:
Next j

endgame:

newSent = Replace(newSent, " ", " ")

replacewords = newSent

End Function
.

Not sure I follow your reasoning Frank. Perhaps try this:

Sub Coloremallatonce()
Dim rng As Range
Set rng = Range("A1,B9,C11:C15,R21,H1,F3")
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With
End Sub


you don't need an "i" or any type of loop. As I see it, the question is,
what does "rng" reference in Runt's case.

If I were runt, I would format the entire rng being checked with the above
settings (all in one go), then as I went through the rng finding the word, I
would change those cells back to normal - end result being the cells without
the workd would be appropriately marked. Now if he is using the replace
method on multiple cells at once, then that wouldn't be a workable solution.

--
Regards,
Tom Ogilvy

"Frank stone" wrote in message
...
untested but try replacing rng with i
I think that vb cant associate rng with i and therfore
does nothing. I'm guessing. and i don't have your data to
test it.
-----Original Message-----
I have a funcion call replacewords() that removes words
form sentneces
if they appear in another cell. I want to highlight those
cells where
the macro fails to find a word. To this end, I add the
following code
to the function...

' Highlight those ENTRIES where a word was not
located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With

but it doesn't seem to be doing anything to the cell
formats at all.
The macro itself works, but I can't get it to have any
effect on cell
formats.

Any ideas? Cheers,

Chris

Here is the entire function...

Option Explicit

Function replacewords(rng As Range, rng2 As Range, _
Optional WithString As String
= "...") As
String

Dim mySent As String
Dim myEnt As String
Dim newSent As String
Dim sentArray As Variant
Dim entArray As Variant
Dim i As Integer
Dim j As Integer
Dim entnum As Integer
Dim mySpace As String

myEnt = rng(1).Value
mySent = rng2(1).Value
newSent = ""

sentArray = Split(mySent, " ", , vbTextCompare)
entArray = Split(myEnt, " ", , vbTextCompare)

i = 0
j = 0

entnum = UBound(entArray, 1) - LBound(entArray, 1) + 1

'if only one word in ENTRY field and it appears in the
sentence then
'replace the word with "..." if identical
If entnum = 1 And InStr(1, mySent, myEnt, vbTextCompare)
Then
newSent = Replace(mySent, myEnt, "...", 1, 1,
vbTextCompare)
GoTo endgame
End If

'if more than one word in ENTRY and exact entry appears
in sentence
then
'replace each word with amount of "..." as was words in
entry
If InStr(1, mySent, myEnt, vbTextCompare) Then
For i = 1 To entnum
mySpace = mySpace & "... "
Next i
newSent = Replace(mySent, myEnt, mySpace, 1, 1,
vbTextCompare)
GoTo endgame
End If

'Otherwise, loop through words in sentence and built a
new setence
'where matching or near matching words with a replaced
by "... "
For j = 0 To UBound(sentArray)
For i = 0 To UBound(entArray)
If LCase(entArray(i)) = LCase(sentArray(j)) Then
newSent = newSent & "... "
GoTo exitloop
End If
If LCase(Mid(entArray(i), 1, 3)) = LCase(Mid
(sentArray(j), 1,
3)) Then
newSent = newSent & "... "
GoTo exitloop
End If
' Highlight those ENTRIES where a word was not
located
With rng
.Interior.ColorIndex = 15
.Interior.Pattern = xlSolid
.Font.Bold = True
.Font.Size = 14
End With
Next i
newSent = newSent & sentArray(j) & " "
exitloop:
Next j

endgame:

newSent = Replace(newSent, " ", " ")

replacewords = newSent

End Function
.