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Will someone please show me an example of using countif
as a worksheet function in VBA. I have used the "Find" function to determine the starting row for the countif. It is stored in a var "c" What is the correct syntax to count the number of rows with a "1" in column B, starting with the row "c". Thanks for your help. |
#2
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Hi
try msgbox application.worksheetfunction.countif(Range("B2 & c & ":B10000"),"1") -- Regards Frank Kabel Frankfurt, Germany "Lee Hunter" schrieb im Newsbeitrag ... Will someone please show me an example of using countif as a worksheet function in VBA. I have used the "Find" function to determine the starting row for the countif. It is stored in a var "c" What is the correct syntax to count the number of rows with a "1" in column B, starting with the row "c". Thanks for your help. |
#3
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Thanks Frank.
I received a syntax error. I believe the " are unbalanced. Did you mean to use Range("B"&c&":B1000").....? This too results in a syntax error. Can you see the probllem? Thanks once again for your help. -----Original Message----- Hi try msgbox application.worksheetfunction.countif(Range("B2 & c & ":B10000"),"1") -- Regards Frank Kabel Frankfurt, Germany "Lee Hunter" schrieb im Newsbeitrag news:583401c48154$4dcbe2e0 ... Will someone please show me an example of using countif as a worksheet function in VBA. I have used the "Find" function to determine the starting row for the countif. It is stored in a var "c" What is the correct syntax to count the number of rows with a "1" in column B, starting with the row "c". Thanks for your help. . |
#4
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You have guessed the typo, but created another problem by not putting a
space around the ampersand. Range("B"&c&":B1000") should be Range("B" & c & ":B1000") But then I showed you that already. -- Regards, Tom Ogilvy wrote in message ... Thanks Frank. I received a syntax error. I believe the " are unbalanced. Did you mean to use Range("B"&c&":B1000").....? This too results in a syntax error. Can you see the probllem? Thanks once again for your help. -----Original Message----- Hi try msgbox application.worksheetfunction.countif(Range("B2 & c & ":B10000"),"1") -- Regards Frank Kabel Frankfurt, Germany "Lee Hunter" schrieb im Newsbeitrag news:583401c48154$4dcbe2e0 ... Will someone please show me an example of using countif as a worksheet function in VBA. I have used the "Find" function to determine the starting row for the countif. It is stored in a var "c" What is the correct syntax to count the number of rows with a "1" in column B, starting with the row "c". Thanks for your help. . |
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