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#1
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Get Open File Name
I am writing a macro in VB but need to open a folder rather than
specific file. As the file is unknown but its location is known. Is there anyone who could assist me with the GET OPEN FILE NAM function which will enable me to have a message box from which I ca choose the relevent file? Many Thanks In Advance Kiz -- Message posted from http://www.ExcelForum.com |
#2
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Get Open File Name
I have come up with the following piece of VB Coding but am still havin
a few problems as I cannot open any files with it. fileToOpen = Application _ .GetOpenFilename("Text Files (*.txt), *.txt") If fileToOpen < False Then MsgBox "Open " & fileToOpen End If For some reason, I cannot open any files with this coding. Is there any one who could assist me with this query? Thank -- Message posted from http://www.ExcelForum.com |
#3
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Get Open File Name
Once you get the name of the file, you have to use:
Workbooks.Open fileToOpen to actually do the open. -- Jim Rech Excel MVP "kiza " wrote in message ... |I have come up with the following piece of VB Coding but am still having | a few problems as I cannot open any files with it. | | fileToOpen = Application _ | GetOpenFilename("Text Files (*.txt), *.txt") | If fileToOpen < False Then | MsgBox "Open " & fileToOpen | End If | | For some reason, I cannot open any files with this coding. | | Is there any one who could assist me with this query? | Thanks | | | --- | Message posted from http://www.ExcelForum.com/ | |
#4
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Get Open File Name
kiza
I have enclosed the full code for opening a text file using tab as th column seperator to change the column seperater to a comma as in a CSV file then chang Tab:=True to Tab:=False and Comma:=False to Comma:=True Sub OpenUserFile() Dim FileToOpen As Variant FileToOpen = Application _ .GetOpenFilename("Text Files (*.txt), *.txt") If FileToOpen = False Then Exit Sub End If MsgBox "Open " & FileToOpen Workbooks.OpenText FileName:=FileToOpen, Origin:=xlWindows _ , StartRow:=1, DataType:=xlDelimited, TextQualifier:=xlDoubleQuote, _ ConsecutiveDelimiter:=False, Tab:=True, Semicolon:=False, Comma:=Fals _ , Space:=False, Other:=False, FieldInfo:=Array(Array(1, 1) End Su -- Message posted from http://www.ExcelForum.com |
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