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I am sure this is simple but I can't figure our where I am going wrong, here is what I have
Length = Len(" & FileNumber4 & " I am trying to assign to the variable named "Length" the number of characters in the variable named "FileNumber4 Where am I going wrong, I have looked around and I though this should work but the value for Length should end up as either a 5 or a 6 and it is telling me it is 17. I am a little lost Thanks for the advice Jim |
#2
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James,
Try this Length = Len(FileNumber4) -- HTH Bob Phillips ... looking out across Poole Harbour to the Purbecks (remove nothere from the email address if mailing direct) "James Stephens" wrote in message ... I am sure this is simple but I can't figure our where I am going wrong, here is what I have. Length = Len(" & FileNumber4 & ") I am trying to assign to the variable named "Length" the number of characters in the variable named "FileNumber4" Where am I going wrong, I have looked around and I though this should work but the value for Length should end up as either a 5 or a 6 and it is telling me it is 17. I am a little lost. Thanks for the advice, Jim |
#3
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Everything enclosed within a pair of double quotes is considered a
literal. So, you are getting the length of the literal string space- ampersand-space-the-letters-that-spell-FileNumber4-space-ampersand- space. To get the length of the contents of FileNumber4 use Len(FileNumber4) -- Regards, Tushar Mehta www.tushar-mehta.com Excel, PowerPoint, and VBA add-ins, tutorials Custom MS Office productivity solutions In article , says... I am sure this is simple but I can't figure our where I am going wrong, here is what I have. Length = Len(" & FileNumber4 & ") I am trying to assign to the variable named "Length" the number of characters in the variable named "FileNumber4" Where am I going wrong, I have looked around and I though this should work but the value for Length should end up as either a 5 or a 6 and it is telling me it is 17. I am a little lost. Thanks for the advice, Jim |
#4
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Thanks guys, that took care of it. Sometimes its so simple you just can't figure it out
Thanks alot for the help Ji ----- Tushar Mehta wrote: ---- Everything enclosed within a pair of double quotes is considered a literal. So, you are getting the length of the literal string space ampersand-space-the-letters-that-spell-FileNumber4-space-ampersand space To get the length of the contents of FileNumber4 use Len(FileNumber4 -- Regards Tushar Meht www.tushar-mehta.co Excel, PowerPoint, and VBA add-ins, tutorial Custom MS Office productivity solution In article , says.. I am sure this is simple but I can't figure our where I am going wrong, here is what I have Length = Len(" & FileNumber4 & " I am trying to assign to the variable named "Length" the number of characters in the variable named "FileNumber4 Where am I going wrong, I have looked around and I though this should work but the value for Length should end up as either a 5 or a 6 and it is telling me it is 17. I am a little lost Thanks for the advice Ji |
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