Alex -

Is your chart a line chart? It will calculate these parameters based on
pseudo X values of {1,2,3,4,5,...}. If your true X values increment by
1, but start far away from 1, your slope will be right but the intercept
will be a mile off. Is your first X value close to 2000?

- Jon
-------
Jon Peltier, Microsoft Excel MVP
Peltier Technical Services
http://PeltierTech.com/Excel/Charts/
_______

Alex A wrote:

I used the two functions slope and Intercept but for some
reason the intercept is coming out wrong.

M = Application.WorksheetFunction.Slope(Range("e25:e28 "),
Range("c25:c28"))

b = Application.WorksheetFunction.Intercept(Range
("e25:e28"), Range("c25:c28"))

The label on the graph shows
y = 14484x + 562698

my slope is 14483.664 (good)
my intercept is -28390146.1562596 (bad)

Thoughts?:
One cell range has the Excel Number datatype
and the other cell range is the Excel Currency datatype