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![]() Hi, I have: Workbook called "Articles". = It contains sheets "super_sheet" and "sub_sheet". = "super_sheet" contains 20,000 rows of data. = "super_sheet" contains the columns "Type", "From Year", "To Year", "Number", "Description", etc ... = Where "Type" is column B, "From Year" is C, "To Year" is D, "Number" is G, "Description" is H I would like to: * Have a button in called "Find Articles" in "sub_sheet". * This button should take the search criteria from cells "b3", "b4", "b5", "b6" in "sub_sheet". * Where cells "b3", "b4", "b5", "b6" in "sub_sheet" are be respectively labeled "Type", "Year", "Number" and "Description". * Where "b3", "b5" and "b6" may each contain may text. Or they may be blank. * Where "b4" may contain a two digit number with no decimals. Or it may be blank. * So when the "Find Articles" button is clicked then the VBA code would find the rows in "super_sheet" whe the super_sheet:column B contains the text found in sub_sheet:b3 AND super_sheet:column C has the number greater than or equal to found in sub_sheet:b4 AND super_sheet:column D has the number less than or equal to found in sub_sheet:b4 AND super_sheet:column G contains the text found in sub_sheet:b5 AND super_sheet:column H contains the text found in sub_sheet:b6 * Note: in the case of columns B, G and H the text should just contain the criteria text. There is no need for an exact match or case sensitivity. * All rows in "super_sheet" that meet the above 5 conditions should be copied and pasted into "sub_sheet" starting at cell e10. * If there are any blanks in "sub_sheet" cells "b3", "b4", "b5", "b6" then the respective condition does not apply and the remaining contitions apply. * If there are all blanks in "sub_sheet" cells "b3", "b4", "b5", "b6" then no conditions apply so do nothing. Can you please give me the VBA code for this "Find Articles" button? Thanks, Luther ------------------------------------------------ ~~ Message posted from http://www.ExcelTip.com/ ~~View and post usenet messages directly from http://www.ExcelForum.com/ |
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