Imagine the following data:

A B C D
1003 0.89 R1 23
1003 0.59 R2 24
2444 0.32 R1 23
2444 0.84 R2 24
1003 1.14 R3 13
1003 0.79 R1 23
1003 0.12 R1 16


WITHOUT using ANY LOOPS (or ADO/SQL), I would like to
retrieve the lowest value for B , where A = 1003 and C =
R1 and D = 23 (affectively criteria from the first row).

In this case the answer should be B=0.79.


Does anybody know a way that this can be done!? (it would
have to work assuming that there were 4000+ rows in the
table)

Try the following:-

=MIN(IF(($A$2:$A$4000=1003)*($C$2:$C$4000="R1")*($ D$2:$D$4000=23),$B$2:$B$4000))

array entered using CTRL+SHIFT+ENTER

Assumes that the 1003 and 23 fields are numeric, but if not then simply enclose
them with quotes, ie:-

=MIN(IF(($A$2:$A$4000="1003")*($C$2:$C$4000="R1")* ($D$2:$D$4000="23"),$B$2:$B$40
00))

or any mixture depending on your data.

--
Regards
Ken....................... Microsoft MVP - Excel
Sys Spec - Win XP Pro / XL2K & XLXP

----------------------------------------------------------------------------
Attitude - A little thing that makes a BIG difference
----------------------------------------------------------------------------



"Bob" wrote in message
...


Imagine the following data:

A B C D
1003 0.89 R1 23
1003 0.59 R2 24
2444 0.32 R1 23
2444 0.84 R2 24
1003 1.14 R3 13
1003 0.79 R1 23
1003 0.12 R1 16


WITHOUT using ANY LOOPS (or ADO/SQL), I would like to
retrieve the lowest value for B , where A = 1003 and C =
R1 and D = 23 (affectively criteria from the first row).

In this case the answer should be B=0.79.


Does anybody know a way that this can be done!? (it would
have to work assuming that there were 4000+ rows in the
table)







---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date: 27/10/2003

Hi Ken,

Thanks for your response.

I tried using the formula you gave me for the
data in the example below, however it doesn't return the
correct result of 0.79.

am I doing something wrong ?

Please advise,

Many thanks,

-----Original Message-----
Try the following:-

=MIN(IF(($A$2:$A$4000=1003)*($C$2:$C$4000="R1") *
($D$2:$D$4000=23),$B$2:$B$4000))

array entered using CTRL+SHIFT+ENTER

Assumes that the 1003 and 23 fields are numeric, but if
not then simply enclose
them with quotes, ie:-

=MIN(IF(($A$2:$A$4000="1003")*($C$2:$C$4000="R1") *
($D$2:$D$4000="23"),$B$2:$B$40
00))

or any mixture depending on your data.

--
Regards
Ken....................... Microsoft MVP -
Excel
Sys Spec - Win XP Pro / XL2K & XLXP

----------------------------------------------------------
------------------
Attitude - A little thing that makes a BIG difference
----------------------------------------------------------
------------------



"Bob" wrote in
message
...


Imagine the following data:

A B C D
1003 0.89 R1 23
1003 0.59 R2 24
2444 0.32 R1 23
2444 0.84 R2 24
1003 1.14 R3 13
1003 0.79 R1 23
1003 0.12 R1 16


WITHOUT using ANY LOOPS (or ADO/SQL), I would like to
retrieve the lowest value for B , where A = 1003 and C =
R1 and D = 23 (affectively criteria from the first row).

In this case the answer should be B=0.79.


Does anybody know a way that this can be done!? (it
would
have to work assuming that there were 4000+ rows in the
table)







---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date:
27/10/2003


.

Just tested again and I still get 0.79 based on your data. Your 0.79 and other
records in that filed are numerical aren't they?? ie there is no possibility of
that data being text. Also, you did array enter the data, so that you see curly
brackets around the formula if you look in the cell. Only other thing to check
is that you have the formula looking for a text or numerical entry depending on
what is in Columns A and C. It MUST be the correct format in the formula that
matches what is in the spreadsheet. If that all fails, then by all means fire
the spreadsheet down to me and i'll take a look, or I can send you my test
worksheet with your example data working.

If you send me anything you need to take the NOSPAM bit out of my email address.

--
Regards
Ken....................... Microsoft MVP - Excel
Sys Spec - Win XP Pro / XL2K & XLXP

----------------------------------------------------------------------------
Attitude - A little thing that makes a BIG difference
----------------------------------------------------------------------------



"Bob" wrote in message
...


Hi Ken,

Thanks for your response.

I tried using the formula you gave me for the
data in the example below, however it doesn't return the
correct result of 0.79.

am I doing something wrong ?

Please advise,

Many thanks,

-----Original Message-----
Try the following:-

=MIN(IF(($A$2:$A$4000=1003)*($C$2:$C$4000="R1") *
($D$2:$D$4000=23),$B$2:$B$4000))

array entered using CTRL+SHIFT+ENTER

Assumes that the 1003 and 23 fields are numeric, but if
not then simply enclose
them with quotes, ie:-

=MIN(IF(($A$2:$A$4000="1003")*($C$2:$C$4000="R1") *
($D$2:$D$4000="23"),$B$2:$B$40
00))

or any mixture depending on your data.

--
Regards
Ken....................... Microsoft MVP -
Excel
Sys Spec - Win XP Pro / XL2K & XLXP

----------------------------------------------------------
------------------
Attitude - A little thing that makes a BIG difference
----------------------------------------------------------
------------------



"Bob" wrote in
message
...


Imagine the following data:

A B C D
1003 0.89 R1 23
1003 0.59 R2 24
2444 0.32 R1 23
2444 0.84 R2 24
1003 1.14 R3 13
1003 0.79 R1 23
1003 0.12 R1 16


WITHOUT using ANY LOOPS (or ADO/SQL), I would like to
retrieve the lowest value for B , where A = 1003 and C =
R1 and D = 23 (affectively criteria from the first row).

In this case the answer should be B=0.79.


Does anybody know a way that this can be done!? (it
would
have to work assuming that there were 4000+ rows in the
table)







---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date:
27/10/2003


.



---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date: 27/10/2003

My apologies, this DOES in fact work and is briliant!!!!!

I didn't enter the formula as an array formula!!

Many thanks,

Supposing I wanted to implement this in VBA?
Is there a VBA equivalent to the way this array formula
works ?


-----Original Message-----
Just tested again and I still get 0.79 based on your
data. Your 0.79 and other
records in that filed are numerical aren't they?? ie
there is no possibility of
that data being text. Also, you did array enter the
data, so that you see curly
brackets around the formula if you look in the cell.
Only other thing to check
is that you have the formula looking for a text or
numerical entry depending on
what is in Columns A and C. It MUST be the correct
format in the formula that
matches what is in the spreadsheet. If that all fails,
then by all means fire
the spreadsheet down to me and i'll take a look, or I can
send you my test
worksheet with your example data working.

If you send me anything you need to take the NOSPAM bit
out of my email address.

--
Regards
Ken....................... Microsoft MVP -
Excel
Sys Spec - Win XP Pro / XL2K & XLXP

----------------------------------------------------------
------------------
Attitude - A little thing that makes a BIG difference
----------------------------------------------------------
------------------



"Bob" wrote in
message
...


Hi Ken,

Thanks for your response.

I tried using the formula you gave me for the
data in the example below, however it doesn't return the
correct result of 0.79.

am I doing something wrong ?

Please advise,

Many thanks,

-----Original Message-----
Try the following:-

=MIN(IF(($A$2:$A$4000=1003)*($C$2:$C$4000="R1") *
($D$2:$D$4000=23),$B$2:$B$4000))

array entered using CTRL+SHIFT+ENTER

Assumes that the 1003 and 23 fields are numeric, but if
not then simply enclose
them with quotes, ie:-

=MIN(IF(($A$2:$A$4000="1003")*($C$2:$C$4000="R1") *
($D$2:$D$4000="23"),$B$2:$B$40
00))

or any mixture depending on your data.

--
Regards
Ken....................... Microsoft
MVP -
Excel
Sys Spec - Win XP Pro / XL2K & XLXP

-------------------------------------------------------
---
------------------
Attitude - A little thing that makes a BIG difference
-------------------------------------------------------
---
------------------



"Bob" wrote in
message
...


Imagine the following data:

A B C D
1003 0.89 R1 23
1003 0.59 R2 24
2444 0.32 R1 23
2444 0.84 R2 24
1003 1.14 R3 13
1003 0.79 R1 23
1003 0.12 R1 16


WITHOUT using ANY LOOPS (or ADO/SQL), I would like to
retrieve the lowest value for B , where A = 1003 and
C =
R1 and D = 23 (affectively criteria from the first
row).

In this case the answer should be B=0.79.


Does anybody know a way that this can be done!? (it
would
have to work assuming that there were 4000+ rows in
the
table)







---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system
(http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date:
27/10/2003


.



---
Outgoing mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.532 / Virus Database: 326 - Release Date:
27/10/2003


.