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Hi All
I want to open an Excel file, change cells and the save the file via Access. This code works fine at home (Running Windows XP & MS Office XP) but when I use the same code at work (Windows NT MS Office 97) it errors. It first errors at the first line of code, Refering to line "SetxlApp = CreateObject("Excel.Application")" saying xlApp is not dimensiond, I then Dim xlApp as Application. Then it errors at line "Set xlBook = xlApp.workbooks.Open("C:\Test.XLS")". At this stage i'm stuck on what to do. Here's the code: Public Sub q() On Error GoTo MError Set xlApp = CreateObject("Excel.Application") Set xlBook = xlApp.workbooks.Open("C:\Test.XLS") Set xlSheet = xlBook.Sheets("Sheet1") Set xlSheet = Nothing xlBook.Save xlBook.Close Set xlBook = Nothing xlApp.Quit Set xlApp = Nothing End MError: MsgBox (Err.Description), vbCritical End Sub -- Please type david.com inplace of no.thanks. Sorry for the inconvenience but fed up of spam mail. |
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This is a "shot in the dark" since I can't replicate the
environment you described, but you could try this alternative code. Set xlApp = CreateObject("Excel.Application") With xlApp.Application .Workbooks.Open("C:\Test.XLS") .Visible = False End With Set xlSheet = xlApp.Workbooks("Test.XLS").Sheets("Sheet1") Good luck, Merjet |
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