Just to mention. Excel would consider the following
0.5 = x^2/(x-2)(3-0.5x)

as

0.5 = ( (x^2) / (x - 2) ) * (3 - 0.5*x)

with a real solution at 5.887850847558446

You may have meant to group the last two items as in the following
= (x^2) / ( (x - 2) * (3 - 0.5*x) )

If this is the case, you would get two imaginary solutions as Bernie
mentioned..

0.05607457622077704 - 0.580119090916421*I
0.05607457622077704 + 0.580119090916421*I
--
Dana DeLouis
Using Windows XP & Office XP
= = = = = = = = = = = = = = = = =


"bbombel" wrote in message
...
is it possible to solve: 0,5= x^2/(x-2)(3-0,5x)?
how can I do it?