Home |
Search |
Today's Posts |
|
#1
![]()
Posted to microsoft.public.excel.misc
|
|||
|
|||
![]()
Hi, to count consecutive improvements, I convert the following:
ColA ColB ColC ColD ColE ColF ColG ColH ColI 10.2% 9.8% 9.4% 9.2% 9.0% 8.7% 8.6% 7.8% 7.9% So it becomes ColS ColT ColU ColV ColW ColX ColY ColZ ColAA Yes Yes Yes Yes Yes Yes Yes No BlankCell Then I apply in Col AA =IF(ISERROR(MATCH("No",S2:Z2,0)-1),8,MATCH("No",S2:Z2,0)-1) I then get a value of 8 It works great because if there is a "No" in ColS, I get a value of 0, if Yes Yes No, I get 2, etc. MY QUESTION: Is there a way to do this without "helper cells" that will work directly with the percent changes instead? I tried a nested if statement, but it doesn't work... A thread concerning the nested if approach is here, but the formula didn't work out correctly (apply it to the above % changes, and you will get 8 instead of 7): http://www.microsoft.com/office/comm...8-2d90ed708e25 A thread that provided me insight using the match formula is he http://groups.google.com/group/micro...fc9e17ac40e014 Thanks for any suggestions... |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
counting consecutive absences | Excel Worksheet Functions | |||
Return Summed Count of Multiple Consecutive Numeric Values | Excel Worksheet Functions | |||
Counting Consecutive Cells that meet Criteria | Excel Discussion (Misc queries) | |||
Counting consecutive periods | Excel Worksheet Functions | |||
Counting number of consecutive zeros at the end of a list | Excel Discussion (Misc queries) |