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#1
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Could someone please help me write a formula to obtain and average of
L5:L25000 of numbers greater than 2?? thanks, Kathy |
#2
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Try this:
=SUMIF(L5:L25000,"2")/COUNTIF(L5:L25000,"2") HTH, Elkar "Kathy" wrote: Could someone please help me write a formula to obtain and average of L5:L25000 of numbers greater than 2?? thanks, Kathy |
#3
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Thank you for your help - just to double check this gives me an average of
the numbers greater than 2? "Elkar" wrote: Try this: =SUMIF(L5:L25000,"2")/COUNTIF(L5:L25000,"2") HTH, Elkar "Kathy" wrote: Could someone please help me write a formula to obtain and average of L5:L25000 of numbers greater than 2?? thanks, Kathy |
#4
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Correct. Any number that is 2 or less will not be involved in the calculation.
"Kathy" wrote: Thank you for your help - just to double check this gives me an average of the numbers greater than 2? "Elkar" wrote: Try this: =SUMIF(L5:L25000,"2")/COUNTIF(L5:L25000,"2") HTH, Elkar "Kathy" wrote: Could someone please help me write a formula to obtain and average of L5:L25000 of numbers greater than 2?? thanks, Kathy |
#5
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Yes- if you'll note in the formula the numbers greater than 2 but not
equal to 2 are considered. |
#6
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=SUMIF(L5:L25000,"2",L5:L25000)/COUNTIF(L5:L25000,"2") generates a
simple average. |
#7
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Thank you very much! Have a great day.
"Dave O" wrote: =SUMIF(L5:L25000,"2",L5:L25000)/COUNTIF(L5:L25000,"2") generates a simple average. |
#8
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I guess I was concerned because the word "average" is not in the formula
"Dave O" wrote: =SUMIF(L5:L25000,"2",L5:L25000)/COUNTIF(L5:L25000,"2") generates a simple average. |
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