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I was trying to interpolate numbers by using Forecast, but it is not the
linear interpolation result I need. I am wondering is there a way to do it? Following is Forecast help example. By using Forecast, the result is 10.6, but if using interpolation, Known Y (7,9) Known X (28,31), the result should be 8.333 Known Y KnownX 6 20 7 28 9 31 15 38 21 40 Formula Description (Result) =FORECAST(30,A2:A6,B2:B6) Predicts a value for y given an x value of 30 (10.60725) Thank you very much in advance !!!!!! |
#2
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I think you are confusing Y and X
-- Kind regards, Niek Otten "Help!!!!!" wrote in message ... I was trying to interpolate numbers by using Forecast, but it is not the linear interpolation result I need. I am wondering is there a way to do it? Following is Forecast help example. By using Forecast, the result is 10.6, but if using interpolation, Known Y (7,9) Known X (28,31), the result should be 8.333 Known Y KnownX 6 20 7 28 9 31 15 38 21 40 Formula Description (Result) =FORECAST(30,A2:A6,B2:B6) Predicts a value for y given an x value of 30 (10.60725) Thank you very much in advance !!!!!! |
#3
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The example fits a straight line using all five values and bases the
forecast on that fitted line. For interpolation between two points, use only the two adjacent values for the straight-line forecast: =FORECAST(30,A3:A4,B3:B4) or =FORECAST(30,{7,9},{28,31}) and the result is 8.3333. - Mike www.mikemiddleton.com "Help!!!!!" wrote in message ... I was trying to interpolate numbers by using Forecast, but it is not the linear interpolation result I need. I am wondering is there a way to do it? Following is Forecast help example. By using Forecast, the result is 10.6, but if using interpolation, Known Y (7,9) Known X (28,31), the result should be 8.333 Known Y KnownX 6 20 7 28 9 31 15 38 21 40 Formula Description (Result) =FORECAST(30,A2:A6,B2:B6) Predicts a value for y given an x value of 30 (10.60725) Thank you very much in advance !!!!!! |
#4
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In article , ?B?SGVscCEhISEh?= wrote:
I was trying to interpolate numbers by using Forecast, but it is not the linear interpolation result I need. I am wondering is there a way to do it? Following is Forecast help example. By using Forecast, the result is 10.6, but if using interpolation, Known Y (7,9) Known X (28,31), the result should be 8.333 Known Y KnownX 6 20 7 28 9 31 15 38 21 40 Formula Description (Result) =FORECAST(30,A2:A6,B2:B6) Predicts a value for y given an x value of 30 (10.60725) Thank you very much in advance !!!!!! You could use the slope and intercept functions and calculate the numbers you ned using those. That way the function doesn't get in the way of what you are trying to do :) Bruce ---------------------------------------- I believe you find life such a problem because you think there are the good people and the bad people. You're wrong, of course. There are, always and only, the bad people, but some of them are on opposite sides. Lord Vetinari in Guards ! Guards ! - Terry Pratchett Caution ===== followups may have been changed to relevant groups (if there were any) |
#5
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![]() You can plot the data & insert a non-linear trendline, using the option to display the quation on the chart, then use that equation to back out your intermediate values. ---GJC -- gjcase ------------------------------------------------------------------------ gjcase's Profile: http://www.excelforum.com/member.php...o&userid=26061 View this thread: http://www.excelforum.com/showthread...hreadid=532437 |
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