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Hoping someone can guide me in this task....
I have a column that contains 4 different types of items (calling them letters to make easier: Q, A, P, L) I need to have a cell at the bottom that basically creates a total count of each item but only if they are certain items. For example here's a sample column: and I only want A's and P's counted to make the total. A Q Q P L L A (the cell would count 2a's, 1p and the number 3 would show up in the total column) Is there a formula that would help with this (I'm assuming some sort of If statement) thanks for taking the time to read this. |
#2
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Assuming that A2:A8 contains your data, try...
=SUMPRODUCT(--ISNUMBER(MATCH(A2:A8,{"A","P"},0))) or =SUMPRODUCT(--ISNUMBER(MATCH(A2:A8,B2:B3,0))) ....where B2:B3 contains A and P. Hope this helps! In article , Chris wrote: Hoping someone can guide me in this task.... I have a column that contains 4 different types of items (calling them letters to make easier: Q, A, P, L) I need to have a cell at the bottom that basically creates a total count of each item but only if they are certain items. For example here's a sample column: and I only want A's and P's counted to make the total. A Q Q P L L A (the cell would count 2a's, 1p and the number 3 would show up in the total column) Is there a formula that would help with this (I'm assuming some sort of If statement) thanks for taking the time to read this. |
#3
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This may be a bit cumbersome but try this (assuming A1 is your start point)
=COUNTIF(A1:A7,"a")+COUNTIF(A1:A7,"P") Tel "Chris" wrote: Hoping someone can guide me in this task.... I have a column that contains 4 different types of items (calling them letters to make easier: Q, A, P, L) I need to have a cell at the bottom that basically creates a total count of each item but only if they are certain items. For example here's a sample column: and I only want A's and P's counted to make the total. A Q Q P L L A (the cell would count 2a's, 1p and the number 3 would show up in the total column) Is there a formula that would help with this (I'm assuming some sort of If statement) thanks for taking the time to read this. |
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