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#1
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If I have =VLOOKUP(date,data,2) and in the next cell down I want
=VLOOKUP(date,data,5) so the col_index_num increments by 3 each time how would I go about doing this so that it can be copied down instead of editing each line by hand? Many Thanks in advance |
#2
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You could incorporate the row function. If, for example, this began in row
2, instead of the 2, enter =3*(row()-2)+2. In row 2 that evaluates to 2. But copy it down to row 3 and it evaluates to 5, etc. "Kia" wrote: If I have =VLOOKUP(date,data,2) and in the next cell down I want =VLOOKUP(date,data,5) so the col_index_num increments by 3 each time how would I go about doing this so that it can be copied down instead of editing each line by hand? Many Thanks in advance |
#3
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It would be more robust to allow the formula to be started (entered) in
*any* row (cell), and still allow the column index to increment by 3 as it's copied down: =VLOOKUP(Date,Data,3*ROWS($1:2)-4) -- HTH, RD ============================================== Please keep all correspondence within the Group, so all may benefit! ============================================== "bpeltzer" wrote in message ... You could incorporate the row function. If, for example, this began in row 2, instead of the 2, enter =3*(row()-2)+2. In row 2 that evaluates to 2. But copy it down to row 3 and it evaluates to 5, etc. "Kia" wrote: If I have =VLOOKUP(date,data,2) and in the next cell down I want =VLOOKUP(date,data,5) so the col_index_num increments by 3 each time how would I go about doing this so that it can be copied down instead of editing each line by hand? Many Thanks in advance |
#4
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Thank you both so much
bpeltzer your's worked but I can not guarantee the formula will begin in row 2 on summary RagDyer I had to edit your a little to this =VLOOKUP(date,data,3*ROWS($1:2)-3) but it does the job I require Many thanks to you both |
#5
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Thanks for the feed-back.
-- Regards, RD --------------------------------------------------------------------------- Please keep all correspondence within the NewsGroup, so all may benefit ! --------------------------------------------------------------------------- "Kia" wrote in message ... Thank you both so much bpeltzer your's worked but I can not guarantee the formula will begin in row 2 on summary RagDyer I had to edit your a little to this =VLOOKUP(date,data,3*ROWS($1:2)-3) but it does the job I require Many thanks to you both |
#6
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Try this, works anywhere on the spreadsheet:
=VLOOKUP($A2,'Sheet2'!$A$2:$IV$65536,COLUMNS($A2:B 2),FALSE) or this (slightly shorter, same results) =VLOOKUP($A2,'Sheet2'!$2:$65536,COLUMNS($A2:B2),FA LSE) "Kia" wrote: If I have =VLOOKUP(date,data,2) and in the next cell down I want =VLOOKUP(date,data,5) so the col_index_num increments by 3 each time how would I go about doing this so that it can be copied down instead of editing each line by hand? Many Thanks in advance |
#7
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or this (slightly shorter, same results)
=VLOOKUP($A2,'Sheet2'!$2:$65536,COLUMNS($A2:B2),F ALSE) Even shorter: =VLOOKUP($A2,Sheet2!$2:$65536,COLUMNS($A:B),0) -- Biff Microsoft Excel MVP "Cyno" wrote in message ... Try this, works anywhere on the spreadsheet: =VLOOKUP($A2,'Sheet2'!$A$2:$IV$65536,COLUMNS($A2:B 2),FALSE) or this (slightly shorter, same results) =VLOOKUP($A2,'Sheet2'!$2:$65536,COLUMNS($A2:B2),FA LSE) "Kia" wrote: If I have =VLOOKUP(date,data,2) and in the next cell down I want =VLOOKUP(date,data,5) so the col_index_num increments by 3 each time how would I go about doing this so that it can be copied down instead of editing each line by hand? Many Thanks in advance |
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