When using the following code with Type 1, numbers, it works perfect. But
when I change the type to 2 (String) to use text as the password, I get a
mismatch error. Can anyone help?
Thanks!

Sub ProtectAllSheets()
'
Dim Password As String
Password = CLng(Application.InputBox(Prompt:="What Password Do You Want To
Use?", Type:=2))
If Password < 1 Then
'do nothing
Else
Worksheets(1).Activate
ActiveSheet.Protect (Password)
End If

End Sub

You can't cast a string to a long when it is not a number string

Sub ProtectAllSheets()
'
Dim Password As String
Password = Application.InputBox(Prompt:="What Password Do You Want To
Use?", Type:=2)
If Password = "False" Then
'do nothing
Else
Worksheets(1).Activate
ActiveSheet.Protect (Password)
End If

End Sub


--
HTH

Bob Phillips

(remove nothere from email address if mailing direct)

"David" wrote in message
...
When using the following code with Type 1, numbers, it works perfect. But
when I change the type to 2 (String) to use text as the password, I get a
mismatch error. Can anyone help?
Thanks!

Sub ProtectAllSheets()
'
Dim Password As String
Password = CLng(Application.InputBox(Prompt:="What Password Do You Want To
Use?", Type:=2))
If Password < 1 Then
'do nothing
Else
Worksheets(1).Activate
ActiveSheet.Protect (Password)
End If

End Sub

Found it! Took the CLng out of the InputBox line and it works great.

"David" wrote:

When using the following code with Type 1, numbers, it works perfect. But
when I change the type to 2 (String) to use text as the password, I get a
mismatch error. Can anyone help?
Thanks!

Sub ProtectAllSheets()
'
Dim Password As String
Password = CLng(Application.InputBox(Prompt:="What Password Do You Want To
Use?", Type:=2))
If Password < 1 Then
'do nothing
Else
Worksheets(1).Activate
ActiveSheet.Protect (Password)
End If

End Sub