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On Tue, 19 Mar 2013 17:50:30 -0700 (PDT), zvkmpw wrote:
=INDEX($A$1:$J$1,1,MATCH(LARGE($A2:$J2,COLUMN()-10),$A2:$J2,0)) Not tested but I think you would get the same result, and not have it be dependent on the intial column, by using: COLUMNS($A:A) |
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