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I am trying to find the count of all the cells that have an F in one column
and also have an A in another column and I'm getting an error. I hope Excel can do this with a simple formula. I don't do macros. Here's an example: 1 A F 2 B F 3 A P 4 A N/A 5 B P 6 A F Basically I am trying to determine how many "A" level requirement have Passed, how many have Failed, how many are N/A and the same for the B level requirements. I've already tallied the total Fails and Passes with a countif for each column. Now I need to find how many of the Fails are As, Bs and Cs. Same for the Passes. Tell me it's simple! |
#2
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For the combination of "A" and "F" try this...
=SUMPRODUCT(--(A1:A6="A"),--(B1:B6="F")) -- Biff Microsoft Excel MVP "Sleepless in NJ" <Sleepless in wrote in message ... I am trying to find the count of all the cells that have an F in one column and also have an A in another column and I'm getting an error. I hope Excel can do this with a simple formula. I don't do macros. Here's an example: 1 A F 2 B F 3 A P 4 A N/A 5 B P 6 A F Basically I am trying to determine how many "A" level requirement have Passed, how many have Failed, how many are N/A and the same for the B level requirements. I've already tallied the total Fails and Passes with a countif for each column. Now I need to find how many of the Fails are As, Bs and Cs. Same for the Passes. Tell me it's simple! |
#3
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If you're using xl2007+, take a look at =countifs() in Excel's help.
If you're using an earlier version: =sumproduct(--(a1:a10="A"),--(b1:b10="F")) Adjust the ranges to match--but you can't use whole columns (except in xl2007+). =sumproduct() likes to work with numbers. The -- stuff changes trues and falses to 1's and 0's. Bob Phillips explains =sumproduct() in much more detail he http://www.xldynamic.com/source/xld.SUMPRODUCT.html And J.E. McGimpsey has some notes at: http://mcgimpsey.com/excel/formulae/doubleneg.html ========= I think I'd use a pivottable. You could get a nice summary table that shows the level in the first column and the various grades across the table. If you've never used pivottables, here are a few links: Debra Dalgleish's pictures at Jon Peltier's site: http://peltiertech.com/Excel/Pivots/pivottables.htm And Debra's own site: http://www.contextures.com/xlPivot01.html John Walkenbach also has some at: http://j-walk.com/ss/excel/files/general.htm (look for Tony Gwynn's Hit Database) Chip Pearson keeps Harald Staff's notes at: http://www.cpearson.com/excel/pivots.htm MS has some at (xl2000 and xl2002): http://office.microsoft.com/downloads/2000/XCrtPiv.aspx http://office.microsoft.com/assistan...lconPT101.aspx Sleepless in NJ wrote: I am trying to find the count of all the cells that have an F in one column and also have an A in another column and I'm getting an error. I hope Excel can do this with a simple formula. I don't do macros. Here's an example: 1 A F 2 B F 3 A P 4 A N/A 5 B P 6 A F Basically I am trying to determine how many "A" level requirement have Passed, how many have Failed, how many are N/A and the same for the B level requirements. I've already tallied the total Fails and Passes with a countif for each column. Now I need to find how many of the Fails are As, Bs and Cs. Same for the Passes. Tell me it's simple! -- Dave Peterson |
#4
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![]() That works! Great! Thanks so much! "T. Valko" wrote: For the combination of "A" and "F" try this... =SUMPRODUCT(--(A1:A6="A"),--(B1:B6="F")) -- Biff Microsoft Excel MVP "Sleepless in NJ" <Sleepless in wrote in message ... I am trying to find the count of all the cells that have an F in one column and also have an A in another column and I'm getting an error. I hope Excel can do this with a simple formula. I don't do macros. Here's an example: 1 A F 2 B F 3 A P 4 A N/A 5 B P 6 A F Basically I am trying to determine how many "A" level requirement have Passed, how many have Failed, how many are N/A and the same for the B level requirements. I've already tallied the total Fails and Passes with a countif for each column. Now I need to find how many of the Fails are As, Bs and Cs. Same for the Passes. Tell me it's simple! . |
#5
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Yes, just as in the post above yours, it works great! I'm using Office 2003
and it worked perfectly. Thanks! "Dave Peterson" wrote: If you're using xl2007+, take a look at =countifs() in Excel's help. If you're using an earlier version: =sumproduct(--(a1:a10="A"),--(b1:b10="F")) Adjust the ranges to match--but you can't use whole columns (except in xl2007+). =sumproduct() likes to work with numbers. The -- stuff changes trues and falses to 1's and 0's. Bob Phillips explains =sumproduct() in much more detail he http://www.xldynamic.com/source/xld.SUMPRODUCT.html And J.E. McGimpsey has some notes at: http://mcgimpsey.com/excel/formulae/doubleneg.html ========= I think I'd use a pivottable. You could get a nice summary table that shows the level in the first column and the various grades across the table. If you've never used pivottables, here are a few links: Debra Dalgleish's pictures at Jon Peltier's site: http://peltiertech.com/Excel/Pivots/pivottables.htm And Debra's own site: http://www.contextures.com/xlPivot01.html John Walkenbach also has some at: http://j-walk.com/ss/excel/files/general.htm (look for Tony Gwynn's Hit Database) Chip Pearson keeps Harald Staff's notes at: http://www.cpearson.com/excel/pivots.htm MS has some at (xl2000 and xl2002): http://office.microsoft.com/downloads/2000/XCrtPiv.aspx http://office.microsoft.com/assistan...lconPT101.aspx Sleepless in NJ wrote: I am trying to find the count of all the cells that have an F in one column and also have an A in another column and I'm getting an error. I hope Excel can do this with a simple formula. I don't do macros. Here's an example: 1 A F 2 B F 3 A P 4 A N/A 5 B P 6 A F Basically I am trying to determine how many "A" level requirement have Passed, how many have Failed, how many are N/A and the same for the B level requirements. I've already tallied the total Fails and Passes with a countif for each column. Now I need to find how many of the Fails are As, Bs and Cs. Same for the Passes. Tell me it's simple! -- Dave Peterson . |
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