Home |
Search |
Today's Posts |
#6
![]()
Posted to microsoft.public.excel.misc
|
|||
|
|||
![]()
I only want to count the "." on the left side of the string until i hit
another character other than a "." "JLatham" wrote: Well, if "left most" means all but the last one, then just modify the formula to =LEN(A1)-LEN(SUBSTITUTE(A1,".","") -1 but if there's some other definition of "left most", then to come up with a solution we need a clearer definition. "TCF" wrote: I have seen how to count the number of occurances of a particular character, but is there a way to limit the count to just the left most characters? here is my example ...PLATE - WELD, TAPPED, .312 - 18 i want to count only the left most "." in this case, it would be 3. If I use the =LEN(A1)-LEN(SUBSTITUTE(A1,".","") i get 4 because of the . in the .312. any help would be appreciated. thanks |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Counting No of character in a string | Excel Worksheet Functions | |||
Counting a Specific Character | Excel Discussion (Misc queries) | |||
Counting # of characters before a certain character | Excel Discussion (Misc queries) | |||
counting a certain character | Excel Discussion (Misc queries) | |||
Counting Cells w/ a certain character in them? | Excel Discussion (Misc queries) |