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Hello,
I'm trying to calculate water overage rates for my Town and could use some help with a formula. A cell contains the number 64258(gallons). For gallons between 5,000 and 15,000, the rate is $1 per 1,000 gallons (10*1), between 15,000 and 25,000 rate is $1.50 per 1000 gallons (10*1.50), and any over 25,000 rate is $1.75 per 1,000. Anyone have any idea how to write the formula? Thanks for any help. JP |