i am doing some caculations in excel cells, my result is in cell A1,
if the result comes "#DIV/0!" then While executing the following macro, VBA
gives me Debug message. The value of A becomes "Error 2007".
How can i solve this problem?


Sub Postmacro()
A = Cells(1, 1).Value
B = 1.5
if(A<0) then
C = B / A
End if
End Sub

Hi,

I don't understand the problem. The line
if(A<0) then
ensures you won't get a #DIV/0 error but you could get a type mismatch. I
suggest you change that line to

If a < 0 And IsNumeric(a) Then


Mike


"Arvind Mane" wrote:

i am doing some caculations in excel cells, my result is in cell A1,
if the result comes "#DIV/0!" then While executing the following macro, VBA
gives me Debug message. The value of A becomes "Error 2007".
How can i solve this problem?


Sub Postmacro()
A = Cells(1, 1).Value
B = 1.5
if(A<0) then
C = B / A
End if
End Sub

On Fri, 26 Sep 2008 00:07:01 -0700, Arvind Mane
wrote:

i am doing some caculations in excel cells, my result is in cell A1,
if the result comes "#DIV/0!" then While executing the following macro, VBA
gives me Debug message. The value of A becomes "Error 2007".
How can i solve this problem?


Sub Postmacro()
A = Cells(1, 1).Value
B = 1.5
if(A<0) then
C = B / A
End if
End Sub



1. It is good practice to explicitly DIM your variables.

You need to test the contents of Cells(1,1) to see if there is an error value:

====================
Option Explicit
Sub Postmacro()
Dim A As Double
Dim r As Range
Dim B As Double
Dim C As Double

Set r = Cells(1, 1)
If IsError(r) Then Exit Sub
A = r.Value
B = 1.5
If (A < 0) Then
C = B / A

End If
End Sub
===================
--ron

Thanks Ron Rosenfeld

"Ron Rosenfeld" wrote:

On Fri, 26 Sep 2008 00:07:01 -0700, Arvind Mane
wrote:

i am doing some caculations in excel cells, my result is in cell A1,
if the result comes "#DIV/0!" then While executing the following macro, VBA
gives me Debug message. The value of A becomes "Error 2007".
How can i solve this problem?


Sub Postmacro()
A = Cells(1, 1).Value
B = 1.5
if(A<0) then
C = B / A
End if
End Sub



1. It is good practice to explicitly DIM your variables.

You need to test the contents of Cells(1,1) to see if there is an error value:

====================
Option Explicit
Sub Postmacro()
Dim A As Double
Dim r As Range
Dim B As Double
Dim C As Double

Set r = Cells(1, 1)
If IsError(r) Then Exit Sub
A = r.Value
B = 1.5
If (A < 0) Then
C = B / A

End If
End Sub
===================
--ron