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places = Array("J3","n3","r3","v3","z3","ad3","ah3"....<53
Hi. Just an idea. Placing 53 quoted strings on one line is a little hard to read and print, as Dave was trying to show. Here is just another idea: Dim s As String Dim Places s = s & "J3 n3 r3 v3 z3 ad3 ah3 al3 ap3 at3 ax3 bb3 bf3 bj3 bn3 br3 bv3 bz3 cd3 " s = s & "ch3 cl3 cp3 ct3 cx3 db3 df3 dj3 dn3 dr3 dv3 dz3 ed3 eh3 el3 ep3 et3 " s = s & "ex3 fb3 ff3 fj3 fn3 fr3 fv3 fz3 gd3 gh3 gl3 gp3 gt3 gx3 hb3 hf3 hj3" Places = Split(s) - - Dana DeLouis "JB" wrote in message ... Hi Dave, I'm not typing in A2, A2 includes a vlookup formula which results in a number 1-52. The first code I had (see below) worked if I typed the data directly into A2, but it wouldn't work when A2 held the results of a formula. I figured it would need just a little "tweaking" (sorry :)) Julia Private Sub Worksheet_Change(ByVal Target As Range) places = Array("J3","n3","r3","v3","z3","ad3","ah3","al3"," ap3","at3","ax3","bb3","bf3","bj3","bn3","br3","bv 3","bz3","cd3","ch3","cl3","cp3","ct3","cx3","db3" ,"df3","dj3","dn3","dr3","dv3","dz3","ed3","eh3"," el3","ep3","et3","ex3","fb3","ff3","fj3","fn3","fr 3","fv3","fz3","gd3","gh3","gl3","gp3","gt3","gx3" ,"hb3","hf3","hj3") If Intersect(Target, Range("a2")) Is Nothing Then Exit Sub End If i = Range("a2").Value Range(places(i - 1)).Select End Sub "Dave Peterson" wrote: It jumped for me. What are you typing in A2? Make sure that events are enabled and that macros are enabled. And that you're typing that number in A2 of the sheet that has the code. JB wrote: I tried it, but it's not working....it won't jump :( (I really appreciate this, is you have any more suggestions, I'm willing to try anything at this point) Julia "Dave Peterson" wrote: Maybe... Option Explicit Private Sub Worksheet_Change(ByVal Target As Range) Dim Places As Variant Dim i As Variant If Target.Cells.Count 1 Then Exit Sub If Intersect(Target, Me.Range("a2")) Is Nothing Then Exit Sub End If Places = Array("J3", "n3", "r3", "v3", "z3", "ad3", "ah3", _ "al3", "ap3", "at3", "ax3", "bb3", "bf3", _ "bj3", "bn3", "br3", "bv3", "bz3", "cd3", _ "ch3", "cl3", "cp3", "ct3", "cx3", "db3", _ "df3", "dj3", "dn3", "dr3", "dv3", "dz3", _ "ed3", "eh3", "el3", "ep3", "et3", "ex3", _ "fb3", "ff3", "fj3", "fn3", "fr3", "fv3", _ "fz3", "gd3", "gh3", "gl3", "gp3", "gt3", _ "gx3", "hb3", "hf3", "hj3") i = Me.Range("a2").Value 'minor validation--if not a nice number, then go to J3. If IsNumeric(i) = False _ Or i UBound(Places) + 1 _ Or i <= LBound(Places) Then i = LBound(Places) + 1 End If If i = LBound(Places) Then i = UBound(Places) + 1 End If Me.Range(Places(i - 1)).Select End Sub JB wrote: Thanks Bob, I just need a little more help (I don't know how to check the bounds :( ) Sorry to ask, but can you help? Julia "Bob Phillips" wrote: Works for me with a formula, but you may want to do some bound checks Private Sub Worksheet_Change(ByVal Target As Range) places = _ Array("J3", "n3", "r3", "v3", "z3", "ad3", "ah3", "al3", "ap3", "at3", "ax3", _ "bb3", "bf3", "bj3", "bn3", "br3", "bv3", "bz3", "cd3", "ch3", "cl3", _ "cp3", "ct3", "cx3", "db3", "df3", "dj3", "dn3", "dr3", "dv3", "dz3", _ "ed3", "eh3", "el3", "ep3", "et3", "ex3", "fb3", "ff3", "fj3", "fn3", _ "fr3", "fv3", "fz3", "gd3", "gh3", "gl3", "gp3", "gt3", "gx3", "hb3", "hf3", "hj3") If Intersect(Target, Range("a2")) Is Nothing Then Exit Sub End If If i = LBound(places) And i <= UBound(places) Then i = Range("a2").Value Range(places(i - 1)).Select End If End Sub -- --- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "JB" wrote in message ... I have the code below that jumps to another cell based on the data entered in A2, but i need to tweak it so that it allows the data in A2 to be the result of a formula and still jump to the specified cell based on the A2 results. Private Sub Worksheet_Change(ByVal Target As Range) places = Array("J3","n3","r3","v3","z3","ad3","ah3","al3"," ap3","at3","ax3","bb3","bf3","bj3","bn3","br3","bv 3","bz3","cd3","ch3","cl3","cp3","ct3","cx3","db3" ,"df3","dj3","dn3","dr3","dv3","dz3","ed3","eh3"," el3","ep3","et3","ex3","fb3","ff3","fj3","fn3","fr 3","fv3","fz3","gd3","gh3","gl3","gp3","gt3","gx3" ,"hb3","hf3","hj3") If Intersect(Target, Range("a2")) Is Nothing Then Exit Sub End If i = Range("a2").Value Range(places(i - 1)).Select End Sub Thanks in advance! Julia -- Dave Peterson -- Dave Peterson |
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