Being new to Macros in Excel I just tried creating a simple exercise as
follows.
I have stored a value in cell j6 (row 1, col 10). I wish to check the value
if it is 300 and if so, store valueof 500 in cell j7(row 1, col 11).

The script I entered in VB script editor. But when I executed the macro, I
encountered error.

defining a integer or string in VB is using
DIM ctr as integer
DIM flag as string.

Pl let me know how to define the cells in VB script(where I want the results
to be stored) i.e.,


Sub Macro1()

'
If j6 300 Then
j7 = 500


End If

'Application.CommandBars("Stop Recording").Visible = False
'Range("J8").Select
'Application.Goto Reference:="Macro1"
ActiveWorkbook.Save
ActiveWindow.SmallScroll Down:=-27
Range("K4").Select
Application.Goto Reference:="Macro1"
Application.WindowState = xlMinimized
Application.Goto Reference:="Macro1"
Application.Run "'dynam PROFORMA.xls'!Macro1"
ActiveWindow.ScrollColumn = 2
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 5
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 1
ActiveWindow.ScrollColumn = 3
Range("K6").Select
ActiveCell.FormulaR1C1 = "300"
Range("K6").Select
ActiveCell.FormulaR1C1 = "301"
Range("J6").Select
ActiveCell.FormulaR1C1 = "301"
Range("K6").Select
ActiveCell.FormulaR1C1 = " "
Range("J6").Select
ActiveWorkbook.Save
Range("J7").Select
Application.Width = 599.25
Application.Height = 429
Application.Run "'dynam PROFORMA.xls'!Macro1"
Application.CommandBars("Exit Design Mode").Visible = False
Range("J6").Select
ActiveWorkbook.Save
ActiveWorkbook.Save
End Sub
Tools - Macros -

--
reply to my posts are welcome
Thanks

hi,
cells are range objects and need not be defined. instead just use the value
property of the range object. to do what you want try this...
Sub test1()
If Range("J6").Value 300 Then
Range("J7").Value = 500
End If
End Sub
variables need defining. same as above only different.
Sub Test2()
Dim jjj6 As Range 'j6 is reserved for vb/xl
Dim jjj7 As Range
Dim c As Long 'variable for do nothing example
Set jjj6 = Cells(10, 6)
Set jjj7 = Cells(10, 7)
'range("J6") is the same as Cells(10, 6)
c = 1 ' do nothing example
If jjj6.Value 300 Then
jjj7.Value = 500
End If
MsgBox "the value of c is " & c 'do nothing example
End Sub
for a list of data types, in vb help type Data Type then click data type
summary.
it will probably been greek to you but there are the types.

hope this helped
regards
FSt1
"NSNR" wrote:

Being new to Macros in Excel I just tried creating a simple exercise as
follows.
I have stored a value in cell j6 (row 1, col 10). I wish to check the value
if it is 300 and if so, store valueof 500 in cell j7(row 1, col 11).

The script I entered in VB script editor. But when I executed the macro, I
encountered error.

defining a integer or string in VB is using
DIM ctr as integer
DIM flag as string.

Pl let me know how to define the cells in VB script(where I want the results
to be stored) i.e.,


Sub Macro1()

'
If j6 300 Then
j7 = 500


End If

'Application.CommandBars("Stop Recording").Visible = False
'Range("J8").Select
'Application.Goto Reference:="Macro1"
ActiveWorkbook.Save
ActiveWindow.SmallScroll Down:=-27
Range("K4").Select
Application.Goto Reference:="Macro1"
Application.WindowState = xlMinimized
Application.Goto Reference:="Macro1"
Application.Run "'dynam PROFORMA.xls'!Macro1"
ActiveWindow.ScrollColumn = 2
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 5
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 1
ActiveWindow.ScrollColumn = 3
Range("K6").Select
ActiveCell.FormulaR1C1 = "300"
Range("K6").Select
ActiveCell.FormulaR1C1 = "301"
Range("J6").Select
ActiveCell.FormulaR1C1 = "301"
Range("K6").Select
ActiveCell.FormulaR1C1 = " "
Range("J6").Select
ActiveWorkbook.Save
Range("J7").Select
Application.Width = 599.25
Application.Height = 429
Application.Run "'dynam PROFORMA.xls'!Macro1"
Application.CommandBars("Exit Design Mode").Visible = False
Range("J6").Select
ActiveWorkbook.Save
ActiveWorkbook.Save
End Sub
Tools - Macros -

--
reply to my posts are welcome
Thanks

Many thanks for the timely reply.

with Regards

--
reply to my posts are welcome


"FSt1" wrote:

hi,
cells are range objects and need not be defined. instead just use the value
property of the range object. to do what you want try this...
Sub test1()
If Range("J6").Value 300 Then
Range("J7").Value = 500
End If
End Sub
variables need defining. same as above only different.
Sub Test2()
Dim jjj6 As Range 'j6 is reserved for vb/xl
Dim jjj7 As Range
Dim c As Long 'variable for do nothing example
Set jjj6 = Cells(10, 6)
Set jjj7 = Cells(10, 7)
'range("J6") is the same as Cells(10, 6)
c = 1 ' do nothing example
If jjj6.Value 300 Then
jjj7.Value = 500
End If
MsgBox "the value of c is " & c 'do nothing example
End Sub
for a list of data types, in vb help type Data Type then click data type
summary.
it will probably been greek to you but there are the types.

hope this helped
regards
FSt1
"NSNR" wrote:

Being new to Macros in Excel I just tried creating a simple exercise as
follows.
I have stored a value in cell j6 (row 1, col 10). I wish to check the value
if it is 300 and if so, store valueof 500 in cell j7(row 1, col 11).

The script I entered in VB script editor. But when I executed the macro, I
encountered error.

defining a integer or string in VB is using
DIM ctr as integer
DIM flag as string.

Pl let me know how to define the cells in VB script(where I want the results
to be stored) i.e.,


Sub Macro1()

'
If j6 300 Then
j7 = 500


End If

'Application.CommandBars("Stop Recording").Visible = False
'Range("J8").Select
'Application.Goto Reference:="Macro1"
ActiveWorkbook.Save
ActiveWindow.SmallScroll Down:=-27
Range("K4").Select
Application.Goto Reference:="Macro1"
Application.WindowState = xlMinimized
Application.Goto Reference:="Macro1"
Application.Run "'dynam PROFORMA.xls'!Macro1"
ActiveWindow.ScrollColumn = 2
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 5
ActiveWindow.ScrollRow = 4
ActiveWindow.ScrollRow = 3
ActiveWindow.ScrollRow = 2
ActiveWindow.ScrollRow = 1
ActiveWindow.ScrollColumn = 3
Range("K6").Select
ActiveCell.FormulaR1C1 = "300"
Range("K6").Select
ActiveCell.FormulaR1C1 = "301"
Range("J6").Select
ActiveCell.FormulaR1C1 = "301"
Range("K6").Select
ActiveCell.FormulaR1C1 = " "
Range("J6").Select
ActiveWorkbook.Save
Range("J7").Select
Application.Width = 599.25
Application.Height = 429
Application.Run "'dynam PROFORMA.xls'!Macro1"
Application.CommandBars("Exit Design Mode").Visible = False
Range("J6").Select
ActiveWorkbook.Save
ActiveWorkbook.Save
End Sub
Tools - Macros -

--
reply to my posts are welcome
Thanks