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#1
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Is there a way to use a cell value as a parm in a canned function?
Using: =INDEX(A5:A748,MATCH(J2,E5:E748,0),1)
The first parm of INDEX is an array spec. Is there a way I can use the value of cell K1 (which would contain A5) and the value of cell L1 (which would contain A748) in the function? |
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#2
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Is there a way to use a cell value as a parm in a canned function?
You can use the INDIRECT function to build a reference from text. Give this
a try... =INDEX(INDIRECT(K1&":"&L1),MATCH(J2,E5:E748,0),1) Rick "Rich" wrote in message ... Using: =INDEX(A5:A748,MATCH(J2,E5:E748,0),1) The first parm of INDEX is an array spec. Is there a way I can use the value of cell K1 (which would contain A5) and the value of cell L1 (which would contain A748) in the function? |
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#3
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Is there a way to use a cell value as a parm in a canned function?
=INDEX(INDIRECT(K1&":"&L1),MATCH(J2,E5:E748,0),1)
However I would probably use =INDEX(INDEX(A:A,K1):INDEX(A:A,L1),MATCH(J2,E5:E74 8,0)) and put 5 in K1 and 748 in L1 that way the formula wouldn't be volatile -- Regards, Peo Sjoblom "Rich" wrote in message ... Using: =INDEX(A5:A748,MATCH(J2,E5:E748,0),1) The first parm of INDEX is an array spec. Is there a way I can use the value of cell K1 (which would contain A5) and the value of cell L1 (which would contain A748) in the function? |
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#4
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Is there a way to use a cell value as a parm in a canned function?
Thanks Rick, worked great.
Peo's worked with this change... =INDEX(INDIRECT("A"&K3&":A"&L3),MATCH(J2,E5:E748,0 )) Hope I got that right. Regads. "Rich" wrote: Using: =INDEX(A5:A748,MATCH(J2,E5:E748,0),1) The first parm of INDEX is an array spec. Is there a way I can use the value of cell K1 (which would contain A5) and the value of cell L1 (which would contain A748) in the function? |
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#5
Posted to microsoft.public.excel.misc
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Is there a way to use a cell value as a parm in a canned function?
Peo's worked fine for me... use exactly what he posted AND make sure you
only have a number in K1 and L1, NOT the cell reference. That is, don't put A5 in K1, just put 5 in there (the formula gets the A from the A:A reference). Rick "Rich" wrote in message ... Thanks Rick, worked great. Peo's worked with this change... =INDEX(INDIRECT("A"&K3&":A"&L3),MATCH(J2,E5:E748,0 )) Hope I got that right. Regads. "Rich" wrote: Using: =INDEX(A5:A748,MATCH(J2,E5:E748,0),1) The first parm of INDEX is an array spec. Is there a way I can use the value of cell K1 (which would contain A5) and the value of cell L1 (which would contain A748) in the function? |
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