Home |
Search |
Today's Posts |
#5
![]()
Posted to microsoft.public.excel.misc
|
|||
|
|||
![]()
I think you're confused. If your formula is
=jan!E10/E2 then the only way you can get #DIV/0 returned is if E2 is 0 (or blank) or if jan!e10 contains a formula that returns #DIV/0. In the former case, it's best to use =IF(E2=0,"",jan!E10/E2) In the latter, use that type of formula in jan!E10 In article , artemis1027 wrote: I have a formula on one spreadsheet that uses data from other spreadsheets in one workbook. The formula is =jan!e10/e2, and repeats down to =jan!e88/e2. This equals a percentage. I am having trouble when jan!e10 is blank, it gives me the #div/0! error, but when I try to do a conditional format, it tells me that I cannot refer to cells on other spreadsheets. Is there something I can do so it either shows a 0 or leaves it blank? Or even makes the font white to match the background until a number is filled in? |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Error: "Excel encountered an error and had to remove some formatti | Excel Discussion (Misc queries) | |||
Counting instances of found text (Excel error? Or user error?) | Excel Worksheet Functions | |||
I have Error 1919 Error Configuring ODBC dataSource Database | Excel Discussion (Misc queries) | |||
Excel 2003 Macro Error - Runtime error 1004 | Excel Discussion (Misc queries) |