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#1
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Multiples of 1000 in cells?
How can I write and embedded IF statement that only occurs in multiples of
1000? |
#2
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Multiples of 1000 in cells?
Your question is not explicit enough to understand what you want. Can you
post a sample of your data and an explanation of what you want to achieve. Regards, OssieMac "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#3
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Multiples of 1000 in cells?
I am trying to create a cash budget. These are the numbers:
(410,700) 99,735 109040 ??? ??? ??? 50,300 50735 50040 The top number is a cash surplus (shortage), the middle number is borrowing for a loan (or repayment) and the bottom number is the ending cash balance. The ending cash balance must always be at least 50,000 and I have to borrow in increents of 1,000. The three middle numbers should be 461,000, (38000), and (59,000) respectively. I cannot figure out how to create a formula to make this work for any combination of numbers. How do I create a formula to make it so that I am either borrowing or repaying money based on the top number that maintains my minimum ending cash balance of 50,000, but is only in increments of 1,000? I was trying to do an imbedded "If" statement, but I can't figure it out. "OssieMac" wrote: Your question is not explicit enough to understand what you want. Can you post a sample of your data and an explanation of what you want to achieve. Regards, OssieMac "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#4
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Multiples of 1000 in cells?
I am trying to create a cash budget. These are the numbers:
(410,700) 99,735 109040 ??? ??? ??? 50,300 50735 50040 The top number is a cash surplus (shortage), the middle number is borrowing for a loan (or repayment) and the bottom number is the ending cash balance. The ending cash balance must always be at least 50,000 and I have to borrow in increents of 1,000. The three middle numbers should be 461,000, (38000), and (59,000) respectively. I cannot figure out how to create a formula to make this work for any combination of numbers. How do I create a formula to make it so that I am either borrowing or repaying money based on the top number that maintains my minimum ending cash balance of 50,000, but is only in increments of 1,000? I was trying to do an imbedded "If" statement, but I can't figure it out. "OssieMac" wrote: Your question is not explicit enough to understand what you want. Can you post a sample of your data and an explanation of what you want to achieve. Regards, OssieMac "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#5
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Multiples of 1000 in cells?
if i say, "if a #<0, then put the # i'm trying to determine up to the next
highest multiple of 1,000" or "If #0, then put the # i'm trying to down to the last multiple of 1,000." -For example, if the number was -410,700 and i was trying to get it to equal 50,000, so i would add 460,700. however, 460,700 can only be increments of 1,000, so since -410,700 is less than zero, i would make 460,000 go up to the next highest multiple of 1,000 which would be 461,000. this keeps my result at greather than or equal to 50,000. HOW WOULD I PUT THAT INTO AN EQUATION?!? "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#6
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Multiples of 1000 in cells?
=IF(A1=0,FLOOR(A1-50000,1000),CEILING(-A1+50000,1000))*SIGN(A1)
With first value in A1, above formula in A2 and copied right, and =A1-A2 entered in A3 and copied right, you get the following resurlts: -410700 99735 109040 -461000 49000 59000 50300 50735 50040 "Confused" wrote: if i say, "if a #<0, then put the # i'm trying to determine up to the next highest multiple of 1,000" or "If #0, then put the # i'm trying to down to the last multiple of 1,000." -For example, if the number was -410,700 and i was trying to get it to equal 50,000, so i would add 460,700. however, 460,700 can only be increments of 1,000, so since -410,700 is less than zero, i would make 460,000 go up to the next highest multiple of 1,000 which would be 461,000. this keeps my result at greather than or equal to 50,000. HOW WOULD I PUT THAT INTO AN EQUATION?!? "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#7
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Multiples of 1000 in cells?
Try
=CEILING(ABS(A1-A3),1000) -- HTH Bob (there's no email, no snail mail, but somewhere should be gmail in my addy) "Confused" wrote in message ... I am trying to create a cash budget. These are the numbers: (410,700) 99,735 109040 ??? ??? ??? 50,300 50735 50040 The top number is a cash surplus (shortage), the middle number is borrowing for a loan (or repayment) and the bottom number is the ending cash balance. The ending cash balance must always be at least 50,000 and I have to borrow in increents of 1,000. The three middle numbers should be 461,000, (38000), and (59,000) respectively. I cannot figure out how to create a formula to make this work for any combination of numbers. How do I create a formula to make it so that I am either borrowing or repaying money based on the top number that maintains my minimum ending cash balance of 50,000, but is only in increments of 1,000? I was trying to do an imbedded "If" statement, but I can't figure it out. "OssieMac" wrote: Your question is not explicit enough to understand what you want. Can you post a sample of your data and an explanation of what you want to achieve. Regards, OssieMac "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
#8
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Multiples of 1000 in cells?
THANK YOU SO MUCH!!!! That worked! You have been a huge help! Thanks again!
"BoniM" wrote: =IF(A1=0,FLOOR(A1-50000,1000),CEILING(-A1+50000,1000))*SIGN(A1) With first value in A1, above formula in A2 and copied right, and =A1-A2 entered in A3 and copied right, you get the following resurlts: -410700 99735 109040 -461000 49000 59000 50300 50735 50040 "Confused" wrote: if i say, "if a #<0, then put the # i'm trying to determine up to the next highest multiple of 1,000" or "If #0, then put the # i'm trying to down to the last multiple of 1,000." -For example, if the number was -410,700 and i was trying to get it to equal 50,000, so i would add 460,700. however, 460,700 can only be increments of 1,000, so since -410,700 is less than zero, i would make 460,000 go up to the next highest multiple of 1,000 which would be 461,000. this keeps my result at greather than or equal to 50,000. HOW WOULD I PUT THAT INTO AN EQUATION?!? "Confused" wrote: How can I write and embedded IF statement that only occurs in multiples of 1000? |
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