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Need VBA code for "Open Dialogue" box
Good morning.
I am using an Access VBA module to control Excel and I need to figure out code that can simply change current directory to a set directory and then show Excel's "Open" Diaglogue box. I am aware that I can use an open command to open a certain file, but I don't want to do that. I want dialogue box and not specify a file. Any suggestions? Thanks Cordially, |
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