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formula for 55% of a cell reference cannot exceed 156?
I am trying to set up a formula in Excel 2000 to determine paycheck
deductions. A+B=C 55% of C cannot exceed $156.00 If it does exceed $156.00, I would like the cell to read $156.00 Thanks for any help! |
formula for 55% of a cell reference cannot exceed 156?
=MIN(156,55%*C1)
"pcue1490" wrote in message ... I am trying to set up a formula in Excel 2000 to determine paycheck deductions. A+B=C 55% of C cannot exceed $156.00 If it does exceed $156.00, I would like the cell to read $156.00 Thanks for any help! |
formula for 55% of a cell reference cannot exceed 156?
I am not 100 % sure I know what you want
do you want the value of C =min(A1-B1,156/.55) or do you want 55% of C to show? =min(.55*(A1-B1),$156.00) or do you want A-B to show unless the 55 % of A-B is greater than 156 =if(.55*(A1-B1)156, 156,(A1-B1) "pcue1490" wrote: I am trying to set up a formula in Excel 2000 to determine paycheck deductions. A+B=C 55% of C cannot exceed $156.00 If it does exceed $156.00, I would like the cell to read $156.00 Thanks for any help! |
formula for 55% of a cell reference cannot exceed 156?
Thank You! Is this considered a conditional formula?
"Bob Umlas" wrote: =MIN(156,55%*C1) "pcue1490" wrote in message ... I am trying to set up a formula in Excel 2000 to determine paycheck deductions. A+B=C 55% of C cannot exceed $156.00 If it does exceed $156.00, I would like the cell to read $156.00 Thanks for any help! |
formula for 55% of a cell reference cannot exceed 156?
You could re-write Bob's formula as:
=IF(55%*C1<156,55%*C1,156) if you specifically want to make it a conditional formula, but I think you will agree that the MIN function is easier to type. Hope this helps. Pete pcue1490 wrote: Thank You! Is this considered a conditional formula? "Bob Umlas" wrote: =MIN(156,55%*C1) "pcue1490" wrote in message ... I am trying to set up a formula in Excel 2000 to determine paycheck deductions. A+B=C 55% of C cannot exceed $156.00 If it does exceed $156.00, I would like the cell to read $156.00 Thanks for any help! |
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